An electrician has 4.1 meters of wire how many strips 7/10 m can he cut . How much wire will he have left

1 answer:

8 0

7/10 m= 0.7 m

4.1÷0.7=5.85

You would round down 5.85 to just 5, because he cannot cut less than a whole strip.

To find the exact amount of wire used in 5 strips:

5×0.7= 3.5

4.1-3.5= 0.6 m will be leftover.

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ANSWER ASAP ITS FOR FINALS

Roman55 [17]

Answer:

9. 66°

10. 44°

11. $2\sqrt{7}$

12. $2\sqrt{3}$

13. 27.3

14. 33.9

15. 22°

16. 24°

Step-by-step explanation:

9. Add 120 + 80 (equals 200) and subtract that from 360 (Because all angles in a quadrilteral add to 360°), this equals 160. Plug the same number in for both variables in the two other angle equations until the two angles add to 160. For shown work on #9, write:

120 + 80 = 200

360 - 200 = 160

12(5) + 6 = 66°

19(5) - 1 = 94°

94 + 66 = 160

10. Because the two sides are marked as congruent, the two angles are as well. This means the unlabeled angle is also 68°. The interior angles of a triangle always add to 180°, so add 68+68 (equals 136) and subtract that from 180, this equals 44. For shown work on #10, write:

68 x 2 = 136

180 - 136 = 44

11. Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #10, write:

a² + b² = c²

a² + 6² = 8²

a² + 36 = 64

a² = 28

a = $\sqrt{28}$

a = $2\sqrt{7}$

12. (Same steps as #11) Use the Pythagorean theorem (a² + b² = c²) (Make sure to plug in the hypotenuse for c). Solve the equation. For shown work on #11, write:

a² + b² = c²

a² + 2² = 4²

a² + 4 = 16

a² = 12

a = $\sqrt{12}$