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Pani-rosa [81]
4 years ago
6

Listed below are the overhead widths​ (in cm) of seals measured from photographs and the weights​ (in kg) of the seals. Construc

t a​ scatterplot, find the value of the linear correlation coefficient​ r, and find the critical values of r using alphaequals0.01. Is there sufficient evidence to conclude that there is a linear correlation between overhead widths of seals from photographs and the weights of the​ seals?
Overhead Width 7.2 7.5 9.7 9.3 8.7 8.2Weight 119 156 243 200 199 188A. Construct a scatterplot

Mathematics
1 answer:
Anarel [89]4 years ago
5 0

Answer and Step-by-step explanation: Scaterplot is a type of graphic which shows the relationship between to variables. In this question, you want to determine if there is a linear relationship between overhead widths of seals and the weights. So, the hypothesis are:

H₀: no linear correlation;

H₁: there is linear correlation;

In this hypothesis test, to reject H₀, the correlation coefficient r of the data set has to be bigger than the critical value from the table.

With α = 0.05 and n = 6, the critical value is 0.811.

The linear correlation is calculated as:

r = n∑xy - ∑x.∑y / √[n∑x² - (∑x)²] [n∑y² - (∑y)²]

r = \frac{6.9632 - 51.1108}{\sqrt{6.439 - (51^{2} )}.6.14482 - (1108^{2} ) }

r = 0.9485

Since r is bigger than the critical value, H₀ is rejected, which means there is enough evidence to conclude that there is linear correlation between overhead widths and the weights.

In the attachments is the scaterplot of the measurements, also showing the relationship.

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Iteru [2.4K]

The polynomial that gives the interest earned after a year will have variables, exponents and constants that are joined by operators.

  • The interest earned after one year is <u>0.018·x</u>

Reasons:

The amount Paul has to invest = $900

The annual interest rate from the savings account = 1.8%

The amount the money market account pays per year = 4.2 %

Required: The polynomial for the interest Paul earned by investing <em>x</em> dollars in the savings account.

Solution:

The interest earned is found using the compound interest formula as follows;

\displaystyle A = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t}}

Where;

A = The amount in the account after one year

P = The original amount invested = x

r = The interest rate offered on the investment = 1.8% = 0.018

t = The time of the investment = 1 year

n = The number of times of application of the interest per period = Once per year

Which gives;

Interest = Amount earned = A - P

Therefore;

\displaystyle Interest, \ I  = \mathbf{P \cdot \left(1 + \frac{r}{n} \right)^{n \cdot t} - P}

Plugging in the values gives;

\displaystyle I  = x \cdot \left(1 + \frac{0.018}{1} \right)^{1 \times 1} - x = x \cdot 1.018^1 - x = 1.018 \cdot x - x = 0.018 \cdot x

The polynomial equation is therefore;

Interest, I = 0.018·x

Using the simple interest formula, we have;

\displaystyle Interest = \mathbf{\frac{P \times r \times t}{100}}

Which gives;

\displaystyle Interest = \frac{x \times 1.8 \times 1}{100}  = 0.018 \cdot x

Interest earned by investing in the savings account for one year, I = 0.018·x

  • The polynomial representing the interest earned is <u><em>I</em></u><u> = 0.018·x</u>

Learn more here:

brainly.com/question/11314161

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