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Pani-rosa [81]
4 years ago
6

Listed below are the overhead widths​ (in cm) of seals measured from photographs and the weights​ (in kg) of the seals. Construc

t a​ scatterplot, find the value of the linear correlation coefficient​ r, and find the critical values of r using alphaequals0.01. Is there sufficient evidence to conclude that there is a linear correlation between overhead widths of seals from photographs and the weights of the​ seals?
Overhead Width 7.2 7.5 9.7 9.3 8.7 8.2Weight 119 156 243 200 199 188A. Construct a scatterplot

Mathematics
1 answer:
Anarel [89]4 years ago
5 0

Answer and Step-by-step explanation: Scaterplot is a type of graphic which shows the relationship between to variables. In this question, you want to determine if there is a linear relationship between overhead widths of seals and the weights. So, the hypothesis are:

H₀: no linear correlation;

H₁: there is linear correlation;

In this hypothesis test, to reject H₀, the correlation coefficient r of the data set has to be bigger than the critical value from the table.

With α = 0.05 and n = 6, the critical value is 0.811.

The linear correlation is calculated as:

r = n∑xy - ∑x.∑y / √[n∑x² - (∑x)²] [n∑y² - (∑y)²]

r = \frac{6.9632 - 51.1108}{\sqrt{6.439 - (51^{2} )}.6.14482 - (1108^{2} ) }

r = 0.9485

Since r is bigger than the critical value, H₀ is rejected, which means there is enough evidence to conclude that there is linear correlation between overhead widths and the weights.

In the attachments is the scaterplot of the measurements, also showing the relationship.

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Answer:

d.

Step-by-step explanation:

To convert a root to a fraction in the exponent, remember this rule:

\sqrt[n]{a^{m}}=a^{\frac{m}{n}}

The index becomes the denominator in the fraction. (The index is the little number in front of the root, "n".) The original exponent remains in the numerator.

In this question, the index is 4.

The index is applied to every base in the equation under the root. The bases are 16, 'x' and 'y'.

\sqrt[4]{16x^{15}y^{17}} = (\sqrt[4]{16})(\sqrt[4]{x^{15}})(\sqrt[4]{y^{17}}) = (2)(x^{\frac{15}{4}}})(y^{\frac{17}{4}}) = 2x^{\frac{15}{4}}}y^{\frac{17}{4}}

To find the quad root of 16, input this into your calculator. Since 2⁴ = 16, \sqrt[4]{16} = 2.

For the "x" and "y" bases, use the rule for converting roots to exponent fractions. The index, 4, becomes the denominator in each fraction.

2x^{\frac{15}{4}}y^{\frac{17}{4}}

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3 years ago
What is the slope of this line?
Marysya12 [62]

Answer:

1/4

Step-by-step explanation:

rise: 1, run: 4

4 0
3 years ago
What fraction is bigger 1/4 or 16 1/3
Evgen [1.6K]
16 1/3 is bigger than 1/4
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Part of the proceeds from a garage sale was $470 worth of $10 and $20 bills. If there were 14 more $10 bills than $20 bills, fin
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There are 25 $10 bills and 11 $20 bills.

Step-by-step explanation:

Given,

Worth of proceeds from garage = $470

Let,

x be the number of $10 bills

y be the number of $20 bills.

According to given situation;

10x+20y=470       Eqn 1

x = y+14                Eqn 2

Putting value of x from Eqn 2 in Eqn 1

10(y+14)+20y=470\\10y+140+20y=470\\30y=470-140\\30y=330

Dividing both sides by 30

\frac{30y}{30}=\frac{330}{30}\\y=11

Putting y=11 in Eqn 2

x=11+14\\x=25

There are 25 $10 bills and 11 $20 bills.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/1279756
  • brainly.com/question/1284310

#LearnwithBrainly

5 0
3 years ago
A blender that normally costs $130 is on sale for 12% off. What is the final cost of the blender if there is also an 8% sales ta
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Answer:

$105.25

Step-by-step explanation:

First we need to know to price of the blender after the sale, so we are going to pay the 88% of the blender's price so the final price without the sale tax is going to be

\$130\times .88=\$ 114.4      (1)

Knowing this price we need to calculate the 8% of the total price

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We substract the result (2) from (1)

\$ 114.4 - \$ 9.152 = 105.248

Rounding this number to nearest cent the final result is:

$105.25

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3 years ago
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