The height of 18-year-old men are approximately normally distributed, with mean of 68 inches and a standard deviation of 3 inche
s. what is the probability that an 18-year-old man selected at random is between 67 and 69 inches tall? round your answer to the nearest thousandths place (3 places).the height of 18-year-old men are approximately normally distributed, with mean of 68 inches and a standard deviation of 3 inches. what is the probability that an 18-year-old man selected at random is between 67 and 69 inches tall? round your answer to the nearest thousandths place (3 places).
1 answer:
The bell curve below shows the location of the mean and the two values of X; 67 and 69
The area under the curve equals to 1 (as probability equals to one)
We want the area between X=67 and X=69
We first need to find the z-score of X=67 and X=69
z-score of X=67 is given by
z-score of X=69 is given by
The area between z-score -0.33 and 0.33 is given by
P(Z<0.33) - P(Z<-0.33)
We need to read off the z-table to find the value of P(Z<0.33) and P(Z<-0.33).
A screenshot of the z-table is shown below
P(Z<-0.33) = 0.3707
P(Z<0.33) = 0.6293
Hence, the probability that an 18-year old man selected at random is between 67 and 69 inches tall is 0.6293-0.3707=0.2586 or 25.86%
The area under the curve equals to 1 (as probability equals to one)
We want the area between X=67 and X=69
We first need to find the z-score of X=67 and X=69
z-score of X=67 is given by
z-score of X=69 is given by
The area between z-score -0.33 and 0.33 is given by
P(Z<0.33) - P(Z<-0.33)
We need to read off the z-table to find the value of P(Z<0.33) and P(Z<-0.33).
A screenshot of the z-table is shown below
P(Z<-0.33) = 0.3707
P(Z<0.33) = 0.6293
Hence, the probability that an 18-year old man selected at random is between 67 and 69 inches tall is 0.6293-0.3707=0.2586 or 25.86%
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