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igomit [66]
3 years ago
11

At a school event, there were 96 girls. The ratio of the number of girls to the number of boys was 4 : 5. After some time, some

boys arrived and th ratio became 2 : 3. How many boys arrived?
Mathematics
1 answer:
TiliK225 [7]3 years ago
6 0
The girls are 4/9 of the total number of boys and girls, so the total number is 9×96/4=216 and there are 5/9×216=120 boys.
Let the extra number of boys be b, then the total becomes 216+b. We have 96 girls and 120+b boys.
The ratio 2/3=96/(120+b).
Cross multiplying: 2(120+b)=3×96=288.
240+2b=288, 2b=288-240=48, b=24.
So 24 boys arrived.
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75 percent of 104 is the same as 80 percent of what number?
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Your answer is 97.5
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3 years ago
Gia opened two savings accounts at two diffrent banks. One account earns an annual 3.4% simple interest, and the other earns hal
dsp73

Interest from first account is :

I_1 = \dfrac{p\times r \times t}{100}\\\\I_1 = \dfrac{509\times 3.4\times 3}{100}\\\\I_1 =\$ 51.918

Interest form second account is :

I_2 = \dfrac{p\times r\times t}{100}\\\\I_2 = \dfrac{509\times 1.7\times 3}{100}\\\\I_2 =  \$25.959

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I = I_1 + I_2 \\\\I = 51.918 + 25.959\\\\I = \$77.877

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5 0
3 years ago
The following data points represent the number of attendees at each of the dance events hosted by Cloy
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1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2: Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3: Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4: Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
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5 0
3 years ago
In 2003, there were about 5.8078 X 10^8 people using the Internet in the world and about 1.6575 X 10^8 of these people were in t
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Answer:

28.5%  Internet users in 2003 were in the United States.    

Step-by-step explanation:

We are given the following in the question:

Number of people using the internet =

5.8078 \times 10^8

Number of people in United States =

1.6575 \times 10^8

Percent of Internet users in 2003 were in the United States =

=\dfrac{\text{Number of users in United States}}{\text{Number of internet user in world}}\times 100\%\\\\=\dfrac{ 1.6575 \times 10^8}{5.8078 \times 10^8}\times 100\%\\\\=28.5\%

Thus, 28.5%  Internet users in 2003 were in the United States.

6 0
3 years ago
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