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Alona [7]
4 years ago
7

David has a checking account. His opening balance on 3/1 was $120. The bank charges a 30¢ fee for each debit card transaction an

d a 20¢ fee for each check. David made the following transactions:
Used debit card for $20 movie tickets on 3/5
Deposited $38 paycheck on 3/12
Transferred $25 to savings account on 3/16
Withdrew $20 cash from ATM on 3/20



What is David’s balance after the transaction on 3/20?
Mathematics
2 answers:
sukhopar [10]4 years ago
7 0
0! David's balance is $0 after the transaction.
Luden [163]4 years ago
6 0
David has zero balance in his account.
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562 ÷ Choose... = 14 R2
Zolol [24]

Answer:

7868

Step-by-step explanation:

⇒ This can be written algebraically (with a variable <em>x</em>) as:

562 ÷ x = 14

⇒ Convert the division as a fraction:

\frac{562}{x} = 14

⇒ Multiply both sides by 562 to get rid of the fraction and to isolate the variable <em>x</em>:

562 · \frac{562}{x} = 14 · 562

⇒ Simplify:

x = 7868

<u>Answer:</u> 7868

<em></em>

<em>Hope this helps!</em> :)

4 0
3 years ago
5x+2y=22. -2x+6y=3 What is the X coordinate of the solution. Round to the nearest tenth
just olya [345]
Multiply first example by 3 and subtract by second example, you will get the following:

3*(5x + 2y) = 3*22   =>  3*5x + 3*2y = 66      =>  15x + 6y = 66
now subtraction:
(15x + 6y) - (-2x + 6y) = 66 - 3
15x + 6y + 2x - 6y = 63
15x + 2x + 6y - 6y = 63
17x = 63
x = 63/17 ≈ 3.705..... and as it says to round to the nearest tenth our answer would be: x = 3.7
8 0
3 years ago
HELP MEEE PLSSSS PLSSS
RideAnS [48]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The cost of a new car is
seraphim [82]

Answer:

$24,000

Step-by-step explanation:

1. Find what 20% of 30,000 is.

20% x 30,000 = 6,000

2. The problem says the cost of a new car is 20% greater than a used car. Subtract the 6,000 from 30,000 to get the cost of the used car.

30,000 - 6,000 = 24,000

3. The cost of the used car is $24,000

5 0
3 years ago
Please someone help me...​
laiz [17]

Step-by-step explanation:

First factor out the negative sign from the expression and reorder the terms

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )}  -  \frac{1}{ \cot(6A)  -  \cot(2A) }

<u>Using trigonometric </u><u>identities</u>

That's

<h3>\cot(x)  =  \frac{1}{ \tan(x) }</h3>

<u>Rewrite the expression</u>

That's

\frac{1}{ - (( \tan(2A) -  \tan(6A)  )} -    \frac{1}{ \frac{1}{ \tan(6A) } }  -  \frac{1}{ \frac{1}{ \tan(2A) } }

We have

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{1}{ \frac{ \tan(2A) -  \tan(6A)  }{ \tan(6A) \tan(2A)  } }</h3>

<u>Rewrite the second fraction</u>

That's

<h3>-  \frac{1}{  \tan(2A) -  \tan(6A)  } -   \frac{ \tan(6A)  \tan(2A) }{ \tan(2A) -  \tan(6A)  }</h3>

Since they have the same denominator we can write the fraction as

-  \frac{1 +  \tan(6A) \tan(2A)  }{ \tan(2A) -  \tan(6A)  }

Using the identity

<h3>\frac{x}{y}  =  \frac{1}{ \frac{y}{x} }</h3>

<u>Rewrite the expression</u>

We have

<h3>-  \frac{1}{ \frac{ \tan(2A)  -  \tan(6A) }{1 +  \tan(6A) \tan(2A)  } }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{ \tan(x) -  \tan(y)  }{1 +  \tan(x)  \tan(y) }  =  \tan(x - y)</h3>

<u>Rewrite the expression</u>

That's

<h3>- \frac{1}{ \tan(2A -6A) }</h3>

Which is

<h3>-  \frac{1}{ \tan( - 4A) }</h3>

<u>Using the trigonometric identity</u>

<h3>\frac{1}{ \tan(x) }  =  \cot(x)</h3>

Rewrite the expression

That's

<h3>-  \cot( - 4A)</h3>

<u>Simplify the expression using symmetry of trigonometric functions</u>

That's

<h3>- ( -  \cot(4A) )</h3>

<u>Remove the parenthesis </u>

We have the final answer as

<h2>\cot(4A)</h2>

As proven

Hope this helps you

6 0
3 years ago
Read 2 more answers
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