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adoni [48]
2 years ago
12

The square of a number plus the number is 182. Find any numbers that satisfy the situation.

Mathematics
1 answer:
Angelina_Jolie [31]2 years ago
6 0

Answer:

x =-14     x=13

Step-by-step explanation:

Let x be the unknown number

x^2 +x = 182

Subtract 182 from each side

x^2 +x -182 = 182-182

x^2 +x -182=0

What two numbers multiply to -182 and add to 1

14*-13 = 182

14-13 =1

(x+14)(x-13) = 0

Using the zero product property

x+14=0  x-13 =0

x =-14     x=13

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6 0
3 years ago
Read 2 more answers
9-17 = 23<br> q=<br> what does q equal?
UkoKoshka [18]

Answer:

q = - 14 / 17

Step-by-step explanation:

9 - 17q = 23

-17q = 23 - 9

-17 q = 14

q = - 14 / 17

3 0
3 years ago
Help???????????!!!!!!!!!!!
Butoxors [25]
Salutations!

12 \frac{2}{3}

- 9 \frac{3}{4}

= \frac{38}{3} 

Then,

- 9 \frac{3}{4}

- \frac{39}{4}

Next, our final answer:

= \frac{35}{12}

= 2 \frac{11}{12} 

Our decimal would be 2.916667

Hopefully This Helps!!!

 
3 0
3 years ago
Consider the function f(x). Select all of the following that include a vertical stretch of f(x)
zhenek [66]

Answer:

F , D, A

Step-by-step explanation:

As we know vertical stretch of f(x)  happens when we chane the value of the patameter a in this general form:

y = a. f(k(x-d))+ c  

when  |a| > 1 because When |a| > 1 (when a is greater than 1), the function is stretched vertically by a dilation factor of |a|.

So we choose, F , D, A

4 0
3 years ago
Read 2 more answers
I need to find the greatest common factor of <img src="https://tex.z-dn.net/?f=40s%5E3t%5E5" id="TexFormula1" title="40s^3t^5" a
solong [7]

Answer:

\large\boxed{GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=2s^3t^4}

Step-by-step explanation:

40s^3t^5=\boxed2\cdot2\cdot2\cdot5\cdot \boxed{s\cdot s\cdot s}\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\\\\2s^4t^4=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\\\\14s^6t^6=\boxed2\cdot7\cdot  \boxed{s\cdot s\cdot s}\cdot s\cdot s\cdot s\cdot \boxed{t\cdot t\cdot t\cdot t}\cdot t\cdot t\\\\GCF(40s^3t^5,\ 2s^4t^4,\ 14s^6t^6)=\boxed2\cdot  \boxed{s\cdot s\cdot s}\cdot\boxed{t\cdot t\cdot t\cdot t}=2s^3t^4

7 0
3 years ago
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