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valina [46]
3 years ago
15

What is the value of x? X___

Mathematics
1 answer:
vladimir1956 [14]3 years ago
4 0

since all angles are the same, then the sides must also be the same measure


therefore

6x-3=3x+6=5x

we can solve for x by taking any 2 equations

6x-3=5x

minus 5x both sides

x-3=0

x=3

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Lesson: 1.08Given this function: f(x) = 4 cos(TTX) + 1Find the following and be sure to show work for period, maximum, and minim
Ber [7]

The given function is

f(x)=4\cos \text{(}\pi x)+1

The general form of the cosine function is

y=a\cos (bx+c)+d

a is the amplitude

2pi/b is the period

c is the phase shift

d is the vertical shift

By comparing the two functions

a = 4

b = pi

c = 0

d = 1

Then its period is

\begin{gathered} \text{Period}=\frac{2\pi}{\pi} \\ \text{Period}=2 \end{gathered}

The equation of the midline is

y_{ml}=\frac{y_{\max }+y_{\min }}{2}

Since the maximum is at the greatest value of cos, which is 1, then

\begin{gathered} y_{\max }=4(1)+1 \\ y_{\max }=5 \end{gathered}

Since the minimum is at the smallest value of cos, which is -1, then

\begin{gathered} y_{\min }=4(-1)+1 \\ y_{\min }=-4+1 \\ y_{\min }=-3 \end{gathered}

Then substitute them in the equation of the midline

\begin{gathered} y_{ml}=\frac{5+(-3)}{2} \\ y_{ml}=\frac{2}{2} \\ y_{ml}=1 \end{gathered}

The answers are:

Period = 2

Equation of the midline is y = 1

Maximum = 5

Minimum = -3

3 0
1 year ago
S = vt + 16t^2, solve for v.
Phoenix [80]
S=vt+16t^2\ \ \ \ \ | subtract\ 16t^2\\\\
S-16t^2=vt\ \ \ \ \ | divide\ by\ t\\\\
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3 years ago
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4 0
3 years ago
What is the y-intercept of the function y= -1/2cos(3/2x)
Flauer [41]

Answer: (0,-1/2)

Step-by-step explanation:

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5 0
4 years ago
Choose the graph below that has an undefined slope.
Ronch [10]

Answer:

The correct option is A.

Step-by-step explanation:

The first line passing through the points (-6,2) and (-6,0).

The slope of a line is

m=\frac{y_2-y_1}{x_2-x_1}

The slope of first line is

m_1=\frac{0-2}{-6-(-6)}=\infty

The second line passing through the points (0,-4) and (-1,1). The slope of second line is

m_2=\frac{1-(-4)}{-1-0}=-5

The third line passing through the points (0,-6) and (2,-6). The slope of third line is

m_3=\frac{-6-(-6)}{2-0}=0

The fourth line passing through the points (0,6) and (-3,-7). The slope of fourth line is


m_4=\frac{-7-6}{-3-0}=\frac{13}{3}

Since the slope of a vertical line is infinity, Therefore option A is correct.

8 0
3 years ago
Read 2 more answers
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