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4 years ago

How do I do this I'm confused

Mathematics

1 answer:

eimsori [14]4 years ago

5 0

Step-by-step explanation:

length can be find out by using the formula

$|AB| = sqrt{(x1-x2)^2+(y1-y2)} \\$

now put values

$\sqrt{(2-2)^2+(0-6)^2} \\$

$\sqrt{0+(-6)^2} \\$

$\sqrt{36 } \\$

$6$

similarly

$|CD| = \sqrt{(12-0)^2+(-10+6)^2} \\$

$\sqrt{144+16} \\$

$\sqrt{160} \\$

$4 \sqrt{10} \\$

and finally

$|EF| = \sqrt{(-3-6)^2+(2-2)^2} \\$

$\sqrt{81} \\$

$9 \\$

i hope u will understand

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Simplify 3√6 divided by 4√6

Alexeev081 [22]

Answer:

-30

Step-by-step explanation:

8 0

4 years ago

Can someone help me with this: Eighty, decreased by three times an number, is the same as five times the number, increased by ei

enot [183]

Eighty, decreased by three times an number, is the same as five times the number, increased by eight. Then the number is 9

<h3><u>Solution:</u></h3>

Given that eighty, decreased by three times an number, is the same as five times the number, increased by eight

<em><u>To find: the number</u></em>

Let the required number be "a"

Let us break the given sentence

<em>Eighty decreased by three times an number = five times the number increased by eight</em>

Here "times" represents multiplication and "decreased" represents subtraction and "increased represents "addition"

80 - three times "a" = 5 times "a" + 8

80 - 3a = 5a + 8

80 - 8 = 5a + 3a

8a = 72

Thus the required number is 9

6 0

3 years ago

At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c

Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=200, p=0.164)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0

3 years ago

How it’s worded is confusing me...

Sergeu [11.5K]

So u hav two numbers one is the multiple of another (so like 2 and 4) ( it can go into the other number) then the least common multiple of the other
I think an answer would be if u do 2 and 4 the LCM would be 2 (don’t know if I’m right not sure about my LCM)

3 0

3 years ago

WILL MARK B!<br> Please I need help I have a quiz

MArishka [77]

Answer:

a) 2x² - x + 3 = x(2x + 1) - 2x

<=> 2x² - x + 3 = 2x² + x - 2x

<=> 3 - x = - x

<=> 3 = 0

=> no solution

b) x/2 - x/3 - x/4 = 1/12

$\frac{6x}{12} - \frac{4x}{12} - \frac{3x}{12} = \frac{1}{12} \\ \\ \frac{ - x}{12} = \frac{1}{12} \\ \\ = > - x = 1 \\ \\ \\ < = > x = 1$

=> the euqation has the solution x = 1

c) |x - 5| = 2|x|

=> x - 5 = 2x

or x - 5 = -2x

<=> x = -5

or 3x = 5

<=> x = -5

x = -5or x = 5/3

d) defined conditions: 2 - x 》 0

<=> x 《 2

we have:

$\sqrt{x + 4} = 2 - x \\ < = > x + 4 = (2 - x) {}^{2} \\ < = > x + 4 = {x}^{2} - 4x + 4 \\ < = > {x}^{2} - 5x = 0 \\ < = > x(x - 5) = 0 \\$

<=> x = 0 (because x 《 2)

$\sqrt{5} = \frac{1}{25 {}^{x} } \\ = > 5 = \frac{1}{25 {}^{2x} } \\ < = > 5.25 {}^{2x} = 1 \\ < = > 5.5 {}^{4x} = 1 \\ < = > 5 {}^{4x + 1} = 1 \\ = > 4x + 1 = 0$

<=> x = -1/4

3 0

3 years ago

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