the average person drinks 1 pint of milk a day . At this rate, how many gallons will a person drink in a leap year

How to flip a desk 5 feet long and then flip another desk and it was 10 feet long what would be the answer

-BARSIC- [3]

I think this may be multiplication so 5 times 10 equls50

6 0

3 years ago

A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he

UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

We dont know the true proportion, so we use $\pi = 0.5$ , which is when we are are going to need the largest sample size.

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.04\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.04}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2$

$n = 600.25$

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.02\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.02}$

$(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2$

$n = 2401$

The minimum sample size is 2401.

4 0

3 years ago

Which equation is a function of x?

Alex787 [66]

The first one I think not sure

5 0

3 years ago

How fast is a car going if its mass is 1000 kg and the force acting on it is 154 N?

Phoenix [80]

Answer:

Only external forces affect the motion of a system, according to Newton's first law. ... force applied to a car produces a much smaller acceleration than when ... Newton's second law states that a net force on an object is responsible for its ... A 1.0-kg mass thus has a weight of 9.8 N on Earth and only about 1.7 N on the Moon.

Step-by-step explanation:

Only external forces affect the motion of a system, according to Newton's first law. ... force applied to a car produces a much smaller acceleration than when ... Newton's second law states that a net force on an object is responsible for its ... A 1.0-kg mass thus has a weight of 9.8 N on Earth and only about 1.7 N on the Moon.

3 0

3 years ago

Is 1/9 >, <, or = {Negative} -4?

kvasek [131]

<u>Answer:</u>

1/9 > -4

because -4 is a negative no less than 0. whereas 1/9 is a positive no greater than 0.

So negative no can't be greater than positive no.

6 0

3 years ago