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3 years ago

the average person drinks 1 pint of milk a day . At this rate, how many gallons will a person drink in a leap year

1 answer:

5 0

Leap years have 366 days, and there are 8 pints per gallon. So we divide the 366 days by the 8 pints per 1 gallon. We end up getting:
45.75 gallons in 1 leap year.

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5. What is the combined weight of the 3/4-lb bags?<br>

Andrew [12]

The answer would be 3.175 kg

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3 years ago

Read 2 more answers

T what point does the curve have maximum curvature? Y = 7ex (x, y) = what happens to the curvature as x → ∞? Κ(x) approaches as

Nookie1986 [14]

Formula for curvature for a well behaved curve y=f(x) is

K(x)= $\frac{|{y}''|}{[1+{y}'^2]^\frac{3}{2}}$

The given curve is y=7 $e^{x}$

${y}''=7e^{x}\\ {y}'=7e^{x}$

k(x)= $\frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

${k(x)}'=\frac{7(e^x)(1+49e^{2x})(49e^{2x}-\frac{1}{2})}{[1+49e^{2x}]^{3}}$

For Maxima or Minima

${k(x)}'=0$

$7(e^x)(1+49e^{2x})(98e^{2x}-1)=0$

→ $e^{x}=0∨ 1+49e^{2x}=0∨98e^{2x}-1=0$

$e^{x}=0 , ∧ 1+49e^{2x}=0$ [not possible ∵there exists no value of x satisfying these equation]

→ $98e^{2x}-1=0$

Solving this we get

x= $-\frac{1}{2}\ln{98}$

As you will evaluate ${k(x})}''$ <0 at x= $-\frac{1}{2}\ln98$

So this is the point of Maxima. we get y=7×1/√98=1/√2

(x,y)=[ $-\frac{1}{2}\ln98$ ,1/√2]

k(x)= $\lim_{x\to\infty } \frac{7e^{x}}{[{1+(7e^{x})^2}]^\frac{3}{2}}$

k(x)= $\frac{7}{\infty}$

k(x)=0

5 0

3 years ago

Plz help plz only I need the answer

TEA [102]

Answer:

The second one

Step-by-step explanation:

4 0

2 years ago

If 1 cost 9p find the cost of 100

damaskus [11]

9p times 100 = 900p or £9

7 0

3 years ago

Write the equation in slope-intercept form y+3=4(x−1) plz do step by step

Rainbow [258]

Answer:y=4x -7

Step-by-step explanation:

The slope intercept form is: y= mx + b

Y+3 = 4(x-1) step one distribute 4

Y+3= 4x - 4 step two subtract 3 from both sides

Y=4x -7

5 0

2 years ago