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3 years ago

If sin theta = 4/5 and theta is in quadrant 2, the value of cot theta is

Mathematics

2 answers:

trasher [3.6K]3 years ago

8 0

Answer:

Cot(theta) = - 0.75 or -3/4

Step-by-step explanation:

The hypotenuse is 5

The y value is 4

We need to find the corresponding x value.

x^2 + y^2 = z^2

X = ?

y = 4

z = 5

x^2 + 4^2 = 5^2

x^2 + 16 = 25

x^2 = 9

Now in this case, you are in quadrant 2, so the x value is - 3

sqrt(x^2) = sqrt(9)

x = - 3

The cot value is the adjacent (x value) / the opposite ( y ) value

Cot(theta) = -3/4

cot(theta) = -0.75

xenn [34]3 years ago

4 0

Answer:

cotθ = -3/4

Step-by-step explanation:

Given:

sinθ = 4/5

θ is in Quadrant II, so cosθ < 0

Recall:

cotθ = cosθ/sinθ

cos²θ + sin²θ = 1

Determine cosθ:

cosθ = -√(1-sin²θ) = -√(1-(4/5)²) = -√(1-16/25) = -√(9/25) = -3/5

Determine cotθ:

cotθ = cosθ/sinθ = (-3/5)/(4/5) = (-3/5)(5/4) = -15/20 = -3/4

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If q(x)=7x^2-1 find q(-9)

liq [111]

For this, we are just going to plug in -9 for every x and then solve the equation:

$q(x)=7x^{2} -1$

$q(-9)=7(-9)^{2} -1$

$q(-9)=7(81)-1$

$q(-9)=566$

Now we know that q(-9) is equal to 566.

3 0

3 years ago

Help answer asap pls ---------

Reika [66]

Answer:

d = 5

Step-by-step explanation:

We want to know what d would be when x = -1, so we can start off by plugging in -1 for x to get the following equation: $\sqrt{8 - (-1)} = 2(-1)+d$ . On the left hand side, 2 negatives become a positive sign, so the -(-1) becomes a +1, and 8+1 would equal 9. On the right hand side, we just multiply 2 and -1 to get -2. So, the equation now looks like this: $\sqrt{9} = d-2$ . We know that $\sqrt{9}$ = 3, so we would get 3 = d-2. THen we would add 2 to both sides to get d = 5. Hope this helps!