Which system of equations can you use to find the roots of the equation? x3 – 10x = x2 – 6 y = x3 – x2 + 10x + 6 y = 0 y = x3 –

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Which system of equations can you use to find the roots of the equation? x3 – 10x = x2 – 6 y = x3 – x2 + 10x + 6 y = 0 y = x3 –

x2 + 10x y = 6 y = x3 – 10x y = x2 – 6

Mathematics

2 answers:

bazaltina [42] · Answer 1 · 2022-05-05T09:16:01+03:00

The system of equations that can be used to find the roots of the equation ${x^3} - 10x = {x^2} - 6$ are $\boxed{y = {x^3} - 10x{\text{ and }}y = {x^2} - 6}$ . Option (c) is correct.

Further explanation:

Given:

The equation is ${x^3} - 10x = {x^2} - 6.$

The options are as follows,

(a). $y = {x^3} - {x^2} + 10x + 6{\text{ and }}y = 0$

(b). $y = {x^3} - {x^2} + 10x {\text{ and }}y = 6$

(c). $y = {x^3} - 10x{\text{ and }}y = {x^2} - 6$

Explanation:

The given equation is ${x^3} - 10x = {x^2} - 6.$

The left hand side of the equation is ${x^3} - 10x.$

The right hand side of the equation is ${x^2} - 6.$

Consider the left hand side and right hand side as $y$ .

$y = {x^2} - 6$ and $y = {x^3} - 10x$

Hence, option (c) is correct.

The system of equations that can be used to find the roots of the equation are $\boxed{y = {x^3} - 10x{\text{ and }}y = {x^2} - 6}$ . Option (c) is correct.

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