Answer:
graph g(x)=1/4 x^2 - 2
Step-by-step explanation:
You are to replace x with (1/2x) in the expression x^2-2
So you have (1/2x)^2-2
1/4 x^2-2
Graph some points for g(x)=1/4 x^2-2
The vertex is (0,-2) and the parabola is open up.
I would graph 2 more points besides the vertex
x | g(x) ordered pairs to graph
----------- (-1,-1.75) and (0,-2) and (1,-1.75)
-1 -1.75
0 -2
1 -1.75
F(x) = x² + x - 20 = x² + 5x - 4x - 20 = x(x + 5) - 4(x + 5) = (x + 5)(x - 4)
f(x) = 0 ⇔ (x + 5)(x - 4) = 0 ⇔ x + 5 = 0 or x - 4 = 0 ⇒ x = -5 or x = 4
Answer: C. x = -5 and x = 4.
Answer:
x = -5, 5
Step-by-step explanation:
-x^2-8=-33
Add 8 to each side
-x^2-8+8=-33+8
-x^2 = -25
Divide each side by -1
x^2 = 25
Take the square root of each side
sqrt(x^2) = ±sqrt(25)
x = ±5
Answer:
A.
Step-by-step explanation:
Surface area of the original cone
When, radius is quadrupled and slant height is reduced to one sixth
Plug the above values of r and
in equation (1), new surface area becomes:

Answer:
Step-by-step explanation:
Volumes of two spheres A and B = 648 cm³ and 1029 cm³
Things to remember:
1). Scale factor of two objects =
[
and
are the radii of two circles]
2). Area scale factor = 
3). Volume scale factor = 
Volume scale factor Or Volume ratio = 
![\frac{r_1}{r_2}=\sqrt[3]{\frac{648}{1029} }](https://tex.z-dn.net/?f=%5Cfrac%7Br_1%7D%7Br_2%7D%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B648%7D%7B1029%7D%20%7D)
![\frac{r_1}{r_2}=\frac{6(\sqrt[3]{3})}{7(\sqrt[3]{3})}](https://tex.z-dn.net/?f=%5Cfrac%7Br_1%7D%7Br_2%7D%3D%5Cfrac%7B6%28%5Csqrt%5B3%5D%7B3%7D%29%7D%7B7%28%5Csqrt%5B3%5D%7B3%7D%29%7D)

Therefore, scale factor =
≈ 6 : 7
Area scale factor Or area ratio = 
= 
≈ 36 : 49
Volume scale factor or Volume ratio = 
= 
≈ 216 : 343