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2 years ago

What is the answer i need help

Mathematics

1 answer:

ss7ja [257]2 years ago

8 0

Answer:

Step-by-step explanation:

add 5+5+7+6+4

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A crab crawls 7ft below sea level. Directly above the crab a bird flies 15 ft above sea level what is the distance between the c

adoni [48]

The crab crawls 7ft below (-7) and the bird flies ft above (15) so the distance between 15 and -7 is 22

4 0

3 years ago

Read 2 more answers

Simplify (y-7) 11. y 4 11y-7 18-y

melisa1 [442]

-y - 718 + 11y413 - 77y412 Answer to your question

6 0

3 years ago

What is the present value of $6,000 to be received at the end of each of eight periods, assuming the first payment occurs at the

Kipish [7]

Answer: Present value = $7200

Step-by-step explanation: Given Principal that is the original amount is $6000

Rate is 10% every fourth year

But the total period is eight.

So the interest would be paid 8/4 = 2 times.

Therefore,

Simple interest

= {principal * rate * no of times}/100

= {$6000*10*2}/100

Simple interest = $1200

Present value

= principal + Simple interest

= $6000 + $1200

= $7200.

6 0

3 years ago

Is (0,0) a solution to this system?

Anuta_ua [19.1K]

Answer:

option-B

Step-by-step explanation:

we are given system of inequality as

$y\leq x^2-4$

$y>2x-1$

now, we can check solution

At (0,0):

we can plug x=0 and y=0

and check inequality

$0\leq 0^2-4$

$0\leq -4$

so, this is FALSE

now, we can check second inequality

$0>2\times 0-1$

$0>-1$

So, this is TRUE

so, option-B

5 0

3 years ago

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A survey study is to be made to estimate the proportion of residents of a certain suburb who favor the construction of a public

lesya [120]

Answer: 601

Step-by-step explanation:

When the prior estimate of population proportion is not given , the formula we apply to find sample size :

$n=0.25(\dfrac{z^*}{E})^2$

, where z* = critical z-value

E=Margin of error

Given : Margin of error = 0.04

Confidence level = 95%

We know that , according to the z-table , the critical value for 95% confidence interval = z*= 1.960

Then, the required sample size : $n=0.25(\dfrac{1.960}{0.04})^2$

$n=0.25(49)^2$

$n=0.25(2401)=600.25\approx601$

Hence, the required minimum sample size = 601

4 0

3 years ago