35 has 4 divisors, hence two factor pairs: 1*35 and 5*7. Each corresponds to a set of perfect squares that differ by 35
One pair is ((35±1)/2)^2 = {17^2, 18^2} = {289, 324}
The other is ((7±5)/2)^2 = {1^2, 6^2} = {1, 36}
Answer:
IM SORRY BUT WHAT KIND OF MATH IS THIS
Step-by-step explanation:
Answer:
No Horiz Asymptote
No Vert Asymptote
Y-int=5
Step-by-step explanation:
You can clearly see when graphing that there is neither a horiz. nor vert. asymptote, and you can see that it intercepts the y-axis at (0,5).
Short Answer: AB
Argument
Take F to be the center. The line segment that IS a diameter or radius must either go through F (that would make the line a diameter) or to be a radius the segment mus end in F and touch the circumference once. See below.
The diameter must not only go through F, it must touch the circumference in two places. EFB is a diameter. So is AFC
The radius must have 1 endpoint at the center and one endpoint on the circumference. DF is a radius.
So what isn't? Answer: AB isn't. It neither goes through F nor is F one of the end points.
Answer: AB
