M ∠ BOA = 360° - 250° = 110°
The sum of all interior angles of the quadrilateral AOBC is 360°
m ∠ BCA = 360° - ( 110° + 90° + 90° ) = 360° - 290° = 70°
Answer: C ) 70°
Answer:
-16
Step-by-step explanation:
-5-(3^2+2)
Parentheses first
-5-(9+2)
-5-(11)
Subtract
-16
hold on i will send in the comments i’m working on it rn
what grade is this and what are the answers i need them to help
Answer:
13.4 x 2 = <em>26.8</em>
<em>12.5</em>
HYPOTENUSE:
10^2 + 12.5^2 = 256.25
Square root of 256.25 = around 16
which would equal 256
<em>16 </em>is your hypotenuse.
26.8 + 12.5 + 16 = 55.3 is your perimeter
