Question

Which expression is equivalent to log c x2-1/5x

Answer 1

Answer
C is the correct answer

㏒(x²-1) - (㏒5 + ㏒x)


Explanation
The law of logarithm says; 
㏒AB = ㏒₃A + ㏒₃B
㏒C/B = ㏒₃C - ㏒₃B
So, the given equation will be,

㏒((x²-1)/5x) = ㏒(x²-1) - ㏒5x
                      = ㏒(x²-1) - (㏒5 + ㏒x)

              

Answer 2

 Hello! For this problem we need to make use of two existing logarithmic properties. These are:

1. $log \frac{M}{N}$ is equal to $log M-logN$
2. $log(MN)$ is equal to $log M+logN$

Following the first property, we can simplify the expression to $log (x^{2}-1)-log(5x)$.

Then, we will use the second property to the term 5x. The final form of the expression would then be $log(x^{2}-1)-(log5+logx)$.

ANSWER: $log(x^{2}-1)-(log5+logx)$  (third option)