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algol [13]
3 years ago
12

Sometimes, when Mendel crossed two pea plants with each other, he obtained a phenotypic ratio of 3:1 purple-flowered pea plants

to white-flowered pea plants. These results are consistent with which set of parents?
Biology
1 answer:
DochEvi [55]3 years ago
4 0

Answer:

<em>Heterozygous purple-flowered parents</em>

Explanation:

<em>A cross involving two heterozygous parents for a dominant trait always segregates in 3:1 phenotypic ratio according to Mendel's law of segregation.</em>

In this case, if purple flower colour is dominant over white flower colour and the trait is represent by P, the heterozygous purple-flowered pea plants will be Pp. If two heterozygous individuals are crossed,

Pp   x   Pp    = PP, Pp, Pp, pp

Since P is a dominant allele, the phenotypic ratio will be 3 purple to 1 white.

<em>Hence, the results are consistent with heterozygous purple-flowered parents.</em>

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