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3 years ago

PLEASE HELP I GIVE THANKS

Mathematics

2 answers:

Evgesh-ka [11]3 years ago

6 0

3. B. 90 degrees clockwise rotation around point C
4. C reflection over CF

Romashka-Z-Leto [24]3 years ago

4 0

The answer is A for question number 3 since it rotatesmaround clockwise.A for number 4.

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A data set consists of the values 2, 6, 3, and 1. If we consider this a population (all the values available), the variance isA.

Hoochie [10]

Answer: E. none of the above

Step-by-step explanation:

The given data values that represents the population:

2, 6, 3, and 1.

Number of values : n=4

Mean of the data values = $\dfrac{\text{Sum of values}}{\text{No. of values}}$

$\dfrac{2+6+3+1}{4}=\dfrac{12}{4}=3$

Sum of the squares of the difference between each values and the mean =

$(2-3)^2+(6-3)^2+(3-3)^2+(1-3)^2$

$=-1^2+3^2+0^2+(-2)^2$

$=1+9+0+4=14$

Now , Variance = (Sum of the squares of the difference between each values and the mean ) ÷ (n)

= (14) ÷ (4)= 3.5

Hence, the variance is 3.5.

Therefore , the correct answer is "E. none of the above".

8 0

3 years ago

Rearrange the equation so m is the independent variable.<br><br> 7m + 2 = 7n - 5

9966 [12]

Answer:

M = n - 1

Step-by-step explanation:

7m + 2 = 7n - 5

Group like terms

7m = 7n - 5 - 2

7m = 7n - 7

7m/7 = 7n /7 - 7/7

M = n - 1

4 0

3 years ago

Read 2 more answers

Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the corre

GaryK [48]

Explanation
: the answer is m=f

8 0

3 years ago

Read 2 more answers

Angle θ is in standard position. If (8, -15) is on the terminal ray of angle θ, find the values of the trigonometric functions.

notsponge [240]

ANSWER

$\sin( \theta) = - \frac{15}{17}$

$\csc( \theta) = - \frac{17}{15}$

$\cos( \theta) = \frac{8}{17}$

$\sec( \theta) = \frac{17}{8}$

$\tan( \theta) = - \frac{15}{8}$

$\cot( \theta) = - \frac{8}{15}$

EXPLANATION

From the Pythagoras Theorem, the hypotenuse can be found.

${h}^{2} = 1 {5}^{2} + {8}^{2}$

${h}^{2} = 289$

$h = \sqrt{289}$

$h = 17$

The sine ratio is negative in the fourth quadrant.

$\sin( \theta) = - \frac{opposite}{hypotenuse}$

$\sin( \theta) = - \frac{15}{17}$

The cosecant ratio is the reciprocal of the sine ratio.

$\csc( \theta) = - \frac{17}{15}$

The cosine ratio is positive in the fourth quadrant.

$\cos( \theta) = \frac{adjacent}{hypotenuse}$

$\cos( \theta) = \frac{8}{17}$

The secant ratio is the reciprocal of the cosine ratio.

$\sec( \theta) = \frac{17}{8}$

The tangent ratio is negative in the fourth quadrant.

$\tan( \theta) = - \frac{opposite}{adjacent}$

$\tan( \theta) = - \frac{15}{8}$

The reciprocal of the tangent ratio is the cotangent ratio

$\cot( \theta) = - \frac{8}{15}$

8 0

3 years ago

Read 2 more answers

HELP ME FAST PLEASE! <br>y varies directly with x, and y=2. What is the value of y when x=5?

stealth61 [152]

my answer would be 10, but I might be wrong

4 0

3 years ago