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steposvetlana [31]
4 years ago
6

Simplify the expression

Mathematics
1 answer:
Grace [21]4 years ago
6 0
(-5+8*i)+(-9+5*i) evaluates to <span>-14+13i</span>
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PLEASE ANSWER ASAP!!! YOUR ANSWER MUST INCLUDE AN EXPLANATION IN ORDER TO RECEIVE POINTS AND THE BRAINLIEST ANSWER! THANKS!!!
marishachu [46]
Solutions 

29\pi / 18 Radians = 29 x <span>\pi / 18 

Replace </span><span>\pi  with 180 

Now we have 

29 x 180 / 18 

29 x 180 = 5220 

5220 / 18 

= 290</span>°
8 0
3 years ago
Read 2 more answers
12. A professor creates a boxplot of test scores for 26 students in a statistics course. What percentage of students scored abov
WARRIOR [948]

Answer:

25%

Step-by-step explanation:

Based on the boxplot given ;

The boxplot can be summarized as follows :

Lower quartile, Q1 = 50 (starting point of the box)

Median (Q2), 50th percentile = 70 (vertical line in between the box)

The upper quartile marks the 75th percentile, Q3 = 81 (end point of the box)

The total distribution is 100% and hence, the percentage above the score 81 will be :

100% - 75% = 25%

4 0
3 years ago
At what rate should $1,000 be invested compounded
marishachu [46]

Answer:

14.9%

Step-by-step explanation:

Using the compound interest formula;

A = P(1+r)^t

A is the amount = $2000

P is the principal = $1000

r is the rate

T is the time = 5 years

Substitute the given values into the formula;

2000 = 1000(1+r)^5

2000/1000 = (1+r)^5

2 = (1+r)^5

\sqrt[5]{2} \\ = 1 + r

r = 1.149 - 1

r = 0.149%

Hence the required rate is  14.9%

6 0
3 years ago
A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years
juin [17]

Answer: 0.55567

Step-by-step explanation:

Given : A certain brand of refrigerator has a useful life that is normally distributed with mean 10 years and standard deviation 3 years. The useful lives of these refrigerators are independent.

i.e.

\mu=10\text{ years}\\\sigma=3\text{ years}

Let X_1 and X_2 are two randomly selected refrigerator's life whose sum will exceed third selected refrigerator X_3 .

So that, X =X_1+X_2-1.9\times X_3

Mean =E(X_1)+E(X_2)-E(X_3)=10+10-1.9\times10 =1

Standard deviation =\sqrt{(Var(X_1)+Var(X_1)+Var(X_1))}

=\sqrt{(3^2+3^2+(1.9\times3)^2)}

=7.1056315694

Z-score : z=\dfrac{X-E[x]}{\sqrt{Var[x]}}=\dfrac{0-1}{7.0156315694}\approx-0.14

Now , The  probability that the total useful life of two(i..e n=2) randomly selected refrigerators will exceed 1.9 times the useful life of a third randomly selected refrigerator would be :-

P(Z>-0.14)=P(Z

Hence, the required probability is 0.55567.

3 0
3 years ago
a 100 point test consists of 2 point questions and 5 point questions. there are a total of 44 questions on the test. how many qu
aalyn [17]
5points t-11
2points -22
8 0
3 years ago
Read 2 more answers
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