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3 years ago

Susan rides her bicycle 5 miles in 2/5 of an hour .at this rate how many miles could she ride in 2 hours

Mathematics

2 answers:

Oksi-84 [34.3K]3 years ago

6 0

Divide 5 by 2 = 2.5 per 1/5 an hour
there are 10 of 1/5 an hour in 2 hours
so 10 X 2.5 = 25 miles in 2 hours

finlep [7]3 years ago

3 0

She rides 1 mile per half hour so she rides 4 miles in 2 hours cuz there is 4 half hours in 2 hours

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A pole casts a 6-foot shadow. If the distance from the top of the pole to the tip of the shadow is

KATRIN_1 [288]

Answer:

8feet high

Step-by-step explanation:

To get the height of the pole, we will use the pythagoras theorem. Let H be the height

H² = 10² -6²

H² = 100 - 36

H² = 64

H = √64

H = 8feet

Hence the pole is 8feet high

3 0

2 years ago

Determine the horizontal vertical and slant asymptote y=x^2+2x-3/x-7

lilavasa [31]

Answer:

<h2>A.Vertical:x=7</h2><h2>Slant:y=x+9</h2>

Step-by-step explanation:

$f(x)=\dfrac{x^2+2x-3}{x-7}\\\\vertical\ asymptote:\\\\x-7=0\qquad\text{add 7 to both sides}\\\\\boxed{x=7}\\\\horizontal\ asymptote:\\\\\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{1-\frac{7}{x}}=\pm\infty\\\\\boxed{not\ exist}$

$slant\ asymptote:\\\\y=ax+b\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{f(x)}{x}\\\\b=\lim\limits_{x\to\pm\infty}(f(x)-ax)\\\\a=\lim\limits_{x\to\pm\infty}\dfrac{\frac{x^2+2x-3}{x-7}}{x}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x(x-7)}=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3}{x^2-7x}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2\left(1+\frac{2}{x}-\frac{3}{x^2}\right)}{x^2\left(1-\frac{7}{x}\right)}=\lim\limits_{x\to\pm\infty}\dfrac{1+\frac{2}{x}-\frac{3}{x^2}}{1-\frac{7}{x}}=\dfrac{1}{1}=1$

$b=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-1x\right)=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x(x-7)}{x-7}\right)\\\\=\lim\limits_{x\to\pm\infty}\left(\dfrac{x^2+2x-3}{x-7}-\dfrac{x^2-7x}{x-7}\right)=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-(x^2-7x)}{x-7}\\\\=\lim\limits_{x\to\pm\infty}\dfrac{x^2+2x-3-x^2+7x}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{9x-3}{x-7}=\lim\limits_{x\to\pm\infty}\dfrac{x\left(9-\frac{3}{x}\right)}{x\left(1-\frac{7}{x}\right)}$

$=\lim\limits_{x\to\pm\infty}\dfrac{9-\frac{3}{x}}{1-\frac{7}{x}}=\dfrac{9}{1}=9\\\\\boxed{y=1x+9}$

8 0

3 years ago

9. What is the difference between an isometric transformation and one that is not isometric? Provide examples to illustrate at l

Sveta_85 [38]

An isometric transformation is a transformation of the objects position, without changing the object itself. There are three types of isometric transformation; translation, reflection, and rotation. Nonisometric transformations change and alter the dimension or shape of an object, like enlargement.

6 0

2 years ago

Factorize<br>3a⁴+18a²-21-2b-3b²

Gnom [1K]

Answer:

the expression is not factorable with rational numbers.

3 0

2 years ago

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ivann1987 [24]

Answer:

Step-by-step explanation:

You can't answer c. There is not enough information. Other than there are 14 boys that went, you know nothing about how many went.

Girls going = (3/5) * 20 = 12

Girls not going = 20 - 12 = 8

4 0

3 years ago