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Dima020 [189]
3 years ago
13

The poster in the library is rhombus shaped. If one side length is 11 inches long, what is the perimeter of the poster?

Mathematics
2 answers:
mixas84 [53]3 years ago
8 0
It iS C C C C C C C C C 
Tpy6a [65]3 years ago
6 0
All sides of a rhombus are equal, so you simply add eleven to itself 4 times.

So the answer would be 44 inches.
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Which number line represents the solution set for the inequality 3(8 – 4x) < 6(x – 5)?
MrMuchimi

The solution to the inequality is x > 3

The number line that represent the solution set will be:

<em>A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the right</em>. The correct option is the second option

<h3>Linear Inequalities </h3>

From the question, we are to determine the number line that represents the solution set for the given inequality

The given inequality is

3(8 – 4x) < 6(x – 5)

First, we will solve the inequality

3(8 – 4x) < 6(x – 5)

Clear the brackets

24 - 12x < 6x - 30

Collect like terms

24 + 30 < 6x + 12x

54 < 18x

Divide both sides by 18

3 < x

∴ x > 3

Hence, the number line that represent the solution set will be:

<em>A number line from negative 5 to 5 in increments of 1. An open circle is at 3 and a bold line starts at 3 and is pointing to the right</em>. The correct option is the second option

Learn more on Linear inequalities here: brainly.com/question/28003708

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8 0
2 years ago
You and three friends own a paint shop. The shop's profit was $536 in the first month. You always divide the profits equally. In
alexandr1967 [171]
C.  $360


$224x4=896 (total profit)

$896 (total) - $536 (first month profit) = $360 (second month profit)
4 0
3 years ago
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Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th
xeze [42]

Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

P:(x - 1)^2 + (y + 6)^2 = 9

Q:(x + 4)^2 + (y + 14)^2 = 4

Solving (a): The distance between both

The equation of a circle is:

(x - h)^2 + (y - k)^2 = r^2

Where

Center: (h,k)

Radius:r

P and Q can be rewritten as:

P:(x - 1)^2 + (y + 6)^2 = 3^2

Q:(x + 4)^2 + (y + 14)^2 = 2^2

So, for P:

Center = (1,-6)

r = 3

For Q:

Center = (-4,-14)

r = 2

The distance between them is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

Where:

Center = (1,-6) --- (x_1,y_1)

Center = (-4,-14) --- (x_2,y_2)

So:

d = \sqrt{(1 - -4)^2 + (-6 - -14)^2

d = \sqrt{(5)^2 + (8)^2

d = \sqrt{25 + 64

d = \sqrt{89

d = 9.4

Solving (b): The radius;

In (a), we have:

r = 3 --- circle P

r = 2 --- circle Q

By comparison

2 < 3

<em>Hence, circle Q has a smaller radius</em>

4 0
3 years ago
&lt;17 and &lt;18 are vertical angles. m &lt;17=(5x+3)(degrees) and m&lt;18=(3x+23)(degrees) find the measure of &lt;18
UNO [17]
I think c is the answer to ur question
7 0
4 years ago
Helpppp me please I forgot how to do this
galben [10]

Answer:

-11

Step-by-step explanation:

plz mark as brainliest.

5 0
3 years ago
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