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Natasha_Volkova [10]
3 years ago
12

4(-8x + 5) - (-33x - 26) =

Mathematics
1 answer:
rosijanka [135]3 years ago
8 0
<h2>4(-8x + 5) - (-33x - 26) =</h2><h2>-32x + 20 + 33x + 26=                      (distributive)</h2><h2>-32x  + 33x + 26 + 20=                     (combine like terms)</h2><h2>  x + 46</h2>

Hope it helps.

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Solve the following equation by factoring. 6x 2 - 5x = 50 {-5/3, 5} {-5/2, 10/3} {-10/3, 5/2}
rosijanka [135]
The correct answer is <span>{-5/2, 10/3}.</span>
6 0
2 years ago
Diameter Radius Area Circumference of= 132
AveGali [126]

Answer:

lets \:  \: find \:  \:  \: the \:  \:  \: radius \\ 2\pi \: r = 132 \\   \frac{2\pi \: r}{2\pi}  =  \frac{132}{2\pi}  \\ r = 21.01

lets \:  \:  \: find \:  \:  \: the \:area \: now \\  = \pi {r}^{2} \\  = \pi \times  {21.01}^{2}   \\  = 1,386.76

lets \: fin d\:  \:  \: the \:  \: diameter \\  = d = 2r \\ =  d = 2 \times 21.01 \\  = d = 42.02

7 0
2 years ago
The Jackson family went out to dinner. The price of the meal was $43.45. The sales tax was 7% of the price of the meal. The tip
brilliants [131]

Answer: 53.40

Step-by-step explanation:

Tax = 7% of 43.45 = 3.04

Tip = 15% of (3.04 + 43.45) = 6.91

Total = 43.45 + 3.04 + 6.91

3 0
2 years ago
A manager of a grocery store wants to determine if consumers are spending more than the national average. The national average i
strojnjashka [21]

The valid conclusions for the manager based on the considered test is given by: Option

<h3>When do we perform one sample z-test?</h3>

One sample z-test is performed if the sample size is large enough (n  > 30) and we want to know if the sample comes from the specific population.

For this case, we're specified that:

  • Population mean = \mu = $150
  • Population standard deviation = \sigma = $30.20
  • Sample mean = \overline{x} = $160
  • Sample size = n = 40 > 30
  • Level of significance = \alpha = 2.5% = 0.025
  • We want to determine if the average customer spends more in his store than the national average.

Forming hypotheses:

  • Null Hypothesis: Nullifies what we're trying to determine. Assumes that the average customer doesn't spend more in the store than the national average. Symbolically, we get: H_0: \mu_0 \leq \mu = 150
  • Alternate hypothesis: Assumes that customer spends more in his store than the national average. Symbolically H_1: \mu_0 > \mu = 150

where \mu_0 is the hypothesized population mean of the money his customer spends in his store.

The z-test statistic we get is:

z = \dfrac{\overline{x} - \mu_0}{\sigma/\sqrt{n}} = \dfrac{160 - 150}{30.20/\sqrt{40}} \approx 2.094

The test is single tailed, (right tailed).

The critical value of z at level of significance 0.025 is 1.96

Since we've got 2.904 > 1.96, so we reject the null hypothesis.

(as for right tailed test, we reject null hypothesis if the test statistic is > critical value).

Thus, we accept the alternate hypothesis that customer spends more in his store than the national average.

Learn more about one-sample z-test here:

brainly.com/question/21477856

3 0
1 year ago
Read 2 more answers
Find the image of A(4,-3) under the transformation r x=2
vlabodo [156]
The is number 3 or c. I hope this helps.
8 0
3 years ago
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