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melomori [17]
3 years ago
5

How to graph 3 points f (x) = -2x + 5

Mathematics
1 answer:
Kisachek [45]3 years ago
5 0
The first one is 0,5 the second one is 1,3 last one is 2,1 
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Eight randomly selected customers at a local grocery store spent the following amounts on groceries in a single visit: $216, $18
chubhunter [2.5K]

Answer:

a) 910

b) 828100

c) 144320

Step-by-step explanation:

a. ∑y

This is the sum of all values of y. So

\sum y = 216 + 184 + 35 + 92 + 142 + 175 + 9 + 57 = 910

b. (∑y)^2

This is the square of the sum, so the square of 910, that we found in the previous item.

910² = 828100

c. ∑y^2

This is the sum of the squares of each amount spent. So

\sum y^2 = 216^2 + 184^2 + 35^2 + 92^2 + 142^2 + 175^2 + 9^2 + 57^2 = 144320

8 0
3 years ago
Vicky jogged 2.75 miles in .5 hour. what was her average rate of speed in miles?
Likurg_2 [28]
Vicky’s average speed is 0.55m/h
6 0
3 years ago
Read 2 more answers
What is 5 x 5 in expanded form<br>​
NikAS [45]

Answer:

5×10°

Hope this helped you!!!

3 0
3 years ago
find the angle between the vectors. (first find the exact expression and then approximate to the nearest degree. ) a=[1,2,-2]. B
SashulF [63]

Answer:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

Step-by-step explanation:

For this case first we need to calculate the dot product of the vectors, and after this if the dot product is not equal to 0 we can calculate the angle between the two vectors in order to see if there are parallel or not.

a=[1,2,-2], b=[4,0,-3,]

The dot product on this case is:

a b= (1)*(4) + (2)*(0)+ (-2)*(-3)=10

Since the dot product is not equal to zero then the two vectors are not orthogonal.

Now we can calculate the magnitude of each vector like this:

|a|= \sqrt{(1)^2 +(2)^2 +(-2)^2}=\sqrt{9} =3

|b| =\sqrt{(4)^2 +(0)^2 +(-3)^2}=\sqrt{25}= 5

And finally we can calculate the angle between the vectors like this:

cos \theta = \frac{ab}{|a| |b|}

And the angle is given by:

\theta = cos^{-1} (\frac{ab}{|a| |b|})

If we replace we got:

\theta = cos^{-1} (\frac{10}{\sqrt{9} \sqrt{25}})=cos^{-1} (\frac{10}{15}) = cos^{-1} (\frac{2}{3}) = 48.190

Since the angle between the two vectors is not 180 or 0 degrees we can conclude that are not parallel

And the anfle is approximately \theta \approx 48

3 0
2 years ago
Quadrilateral ABCD has vertices at: A(0,7),B(10,9),C(12,-1),D(2,-3)
Svetach [21]

Answer: the answer is c

Step-by-step explanation:

your welcome

7 0
3 years ago
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