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Bess [88]
3 years ago
8

HELP!!!!

Mathematics
1 answer:
8090 [49]3 years ago
6 0
1,4,4,4,5,5,6,6,6,6,7,7,8,8,10

minimum = 1
Q1 = 4
Q2 (median) = 6
Q3 = 7
maximum = 10

The beginning and end of the " box " are Q1 and Q3.....4 and 7

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8 0
3 years ago
Read 2 more answers
5t=9y + 22 solve for y
inna [77]
Solve for y:
5 t = 9 y + 22
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5 0
4 years ago
Waldo works eight hours and produces 7 units of goods per hour. Emerson works six hours and produces 10 units of goods per hour.
Phoenix [80]

Answer:  Option 'c' is correct.

Step-by-step explanation:

Since we have given that

In case of Waldo:

Number of hours they work = 8

Number of units per hour = 7 units

So, Output would be

8\times 7\\\\=56\ units

In case of Emerson:

Number of hours they work = 6 hours

Number of units per work = 10 units

So,Output would be

10\times 6=60\ units

Hence, Emerson’s productivity and output are greater than Waldo’s.

Therefore, Option 'c' is correct.

8 0
4 years ago
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