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daser333 [38]
3 years ago
5

Lola dice Argos mi perro tiene 10 kg menos que roco cuantos kilogramos tiene argos

Mathematics
1 answer:
Elena L [17]3 years ago
7 0

Answer:

A=R-10

Step-by-step explanation:

The problem is:

<em>Lola says: Argos, my dog, has 10 kilograms less than Roco. How much kilograms Argos has?</em>

<em />

This problem is about algebraic language. We just need to express the ordinaty language into an equation.

We know the words less means difference. So, let's call A Argos' weight and R Roco's weight. We can expresse the given problem as

A=R-10

Notice that we applied a difference due to the word "less" in the problem.

Therefore, Argo's weight is given by the expression

A=R-10

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What are the fourth roots of 6+6√(3i) ?
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Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

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∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

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