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2 years ago

P^7 x p = ? please answer

Mathematics

2 answers:

swat322 years ago

7 0

Answer:

$p^{8}$

Step-by-step explanation:

In exponent multiplication, if base are same, add the exponents

$a^{m}*a^{n} = a^{m+n}\\\\\\p^{7}* p = p^{7+1} = p^{8}$

Rudiy272 years ago

4 0

Answer:

Your answer is p^8

Step-by-step explanation:

p^7 × p

p^7 + 1

p^8

Please!

Mark me brainlist

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Evaluate the following expression if x= 2.14<br> 3.35x + 25 - 2x

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Answer:

The final answer is 27.889 (Feel free to round it)

Step-by-step explanation:

3.35 x 2.14 = 7.169

7.169 + 25 = 32.169

2 x 2.14 = 4.28

32.169 - 4.28 = 27.889

Can I have brainliest? It would help me out, if not thanks anyways! Hope this helped and have a nice day!

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Write the relation below as a set of ordered pairs and state if it is a function. If it is not a function, explain why.

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This is a linear function. Let diameter (inches) be x, circumference (inches) be y, observe that the value of y/x is always 3.14. For example, 15.7/5=31.4/10=...=3.14. Therefore, this is not only a function (one to one correspondence from x to y), it's also a linear function that can be represented as y=3.14x.

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3 years ago

A recent study suggested that 70% of all eligible voters will vote in the next presidential election. Suppose 20 eligible voters

natita [175]

Answer:

0.0479 = 4.79% probability that fewer than 11 of them will vote

Step-by-step explanation:

For each voter, there are only two possible outcomes. Either they will vote, or they will not. The probability of a voter voting is independent of any other voter, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

70% of all eligible voters will vote in the next presidential election.

This means that $p = 0.7$

20 eligible voters were randomly selected from the population of all eligible voters.

This means that $n = 20$

What is the probability that fewer than 11 of them will vote?

This is:

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 10) = C_{20,10}.(0.7)^{10}.(0.3)^{10} = 0.0308$

$P(X = 9) = C_{20,9}.(0.7)^{9}.(0.3)^{11} = 0.0120$

$P(X = 8) = C_{20,8}.(0.7)^{8}.(0.3)^{12} = 0.0039$

$P(X = 7) = C_{20,7}.(0.7)^{7}.(0.3)^{13} = 0.0010$

$P(X = 6) = C_{20,10}.(0.7)^{6}.(0.3)^{12} = 0.0002$

$P(X = 5) = C_{20,5}.(0.7)^{5}.(0.3)^{15} \approx 0$

The probability of 5 or less voting is very close to 0, so they will not affect the outcome. Then

$P(X < 11) = P(X = 10) + P(X = 9) + P(X = 8) + P(X = 7) + P(X = 6) + P(X = 5) + P(X = 4) + P(X = 3) + P(X = 2) + P(X = 1) + P(X = 0) = 0.0308 + 0.0120 + 0.0039 + 0.0010 + 0.0002 = 0.0479$

0.0479 = 4.79% probability that fewer than 11 of them will vote

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