All categories

4 years ago

How do you find the iqr

Mathematics

2 answers:

Maurinko [17]4 years ago

5 0

Answer:

Find the median: (the middle number in the data set).

Find both the upper and lower quartile.

The subtract the upper quartile to the lower quartile, and you get the final answer of an interquartile range.

castortr0y [4]4 years ago

4 0

The interquartile range (IQR) is the difference between the third and first quartiles $Q_3-Q_1$ .

You might be interested in

Find the equation for the line containing the points (-2,-5) and (6,3)

kow [346]

Answer:

y = x - 3

Step-by-step explanation:

Do rise/run to find the slope

8/8 = 1

y = x + b

Plug in a point to find the y-intercept

-5 = -2 + b

-3 = b

The equation will be y = x - 3

5 0

4 years ago

10. Which inverse operation would be used to verify the following equation? 54 ÷ 9 = 6 A. 9 − 6 = 3 B. 9 + 6 = 15 C. 54 ÷ 6 = 9

Lana71 [14]

The first thing we have is the following equation:
54 ÷ 9 = 6
Let's multiply both sides by 9 to not alter the equality:
(54 ÷ 9) * 9 = 6 * 9
Rewriting we have:
54 = 6 * 9
Answer:
An inverse operation that would be used to verify the equation is:
D. 9 × 6 = 54

4 0

3 years ago

Read 2 more answers

In June, Jasmine earned $1200 in commission. In July, her commission decreased by 7% Write an expression that can be used to fin

aniked [119]

Answer:

$1116

Step-by-step explanation:

8 0

3 years ago

Expression 1 6 x 7 – 3^2 x 9 + 4^3 =

matrenka [14]

16x7-3^2x9+4^3

2x5+4x2+6-2x2-1

i hope that helps

8 0

3 years ago

today each cookie costs 0.75 less than the normal price. pight now if you buy 7 of them it will only cost you 2.80 . writw an eq

lbvjy [14]

The normal price of each cookie is $1.15 derived from the equation, c =today price of each cookie + 0.75

<u>Solution:</u>

Given, Today each cookie costs 0.75 less than the normal price.

Right now if you buy 7 of them it will only cost you 2.80

We have to write an equation to determine the normal price of each cookie(c)

And, we are given that, today 7 cookies cost 2.80

Let the cost of one cookie today be “n”

Then we get,

Today 7 cookies ⇒ 2.8

Then, 1 cookie ⇒ n

By criss cross multiplication we get,

$\begin{array}{l}{7 \times n=2.8 \times 1} \\\\ {\rightarrow 7 n=2.8} \\\\ {\rightarrow n=0.4}\end{array}$

Which means that, each cookie costs $0.4 today

Now, we know that,

<em>normal price of each cookie, c = today price of each cookie + $ 0.75 </em>

c = 0.4 + 0.75

c= 1.15

Hence, the normal cost of each cookie is $1.15 derived from the equation, c = today price of each cookie + 0.75

3 0

3 years ago