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4 years ago

Find the equation for the line containing the points (-2,-5) and (6,3)

Mathematics

1 answer:

kow [346]4 years ago

5 0

Answer:

y = x - 3

Step-by-step explanation:

Do rise/run to find the slope

8/8 = 1

y = x + b

Plug in a point to find the y-intercept

-5 = -2 + b

-3 = b

The equation will be y = x - 3

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Through: (1, -3), slope = -4<br> A) y=-x+4 B) y = x +4<br> C) y = 4x + 1 D) y=-4x + 1

Rudik [331]

Answer:

D) y = -4x + 1

8 0

3 years ago

Please help me out.....................

larisa86 [58]

Answer:

y = 10

Step-by-step explanation:

The opposite sides of a parallelogram are congruent, hence

x + 10 = 110 - 4x ( add 4x to both sides )

5x + 10 = 110 ( subtract 10 from both sides )

5x = 100 ( divide both sides by 5 )

x = 20

Using the other pair of congruent sides, then

3y - 10 = 2x - 20 = (2 × 20) - 20 = 40 - 20 = 20, thus

3y - 10 = 20 ( add 10 to both sides )

3y = 30 ( divide both sides by 3 )

y = 10

4 0

3 years ago

What is the area of ABC?

notsponge [240]

Let D be the Intersection of Height of the Triangle and Base of the Triangle BC

From the Figure, We can notice that Triangle ADB is a Right angled Triangle.

We know that, In a Right angled Triangle :

$\bigstar$ (Hypotenuse)² = (First Leg)² + (Second leg)²

In Triangle, ADB : AB is the Hypotenuse, AD is the First leg and BD is the Second leg

Given : AB = 15 and BD = 9

Substituting the values, We get :

$:\implies$ (15)² = (AD)² + (9)²

$:\implies$ 225 = (AD)² + 81

$:\implies$ (AD)² = 225 - 81

$:\implies$ (AD)² = 144

$:\implies$ (AD)² = (12)²

$:\implies$ AD = 12

We know that, In a Right angled Triangle :

$\bigstar\;\;\boxed{\mathsf{Tan\theta = \dfrac{Opposite\;Side}{Adjacent\;Side}}}$

Now, Consider Triangle ADC : With respect to 45° Angle, AD is the Opposite Side and DC is the Adjacent Side

$:\implies \mathsf{In\;Triangle\;ADC,\;Tan45^{\circ} = \dfrac{AD}{DC}}$

$\mathsf{:\implies 1 = \dfrac{12}{DC}}$

$:\implies$ DC = 12

$:\implies$ Total Length of the Base (BC) = BD + DC

$:\implies$ Total Length of the Base (BC) = 9 + 12

$:\implies$ Total Length of the Base (BC) = 21

We know that, Area of the Triangle is given by :

$\bigstar\;\;\boxed{\mathsf{Area = \dfrac{1}{2} \times Base \times Height}}$

In Triangle, ABC : AD is the Height and BC is the Base

$:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times BC \times AD}$

$:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = \dfrac{1}{2} \times 21 \times 12}$

$:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = (21 \times 6)}$

$:\implies \mathsf{Area\;of\;the\;Triangle\;ABC = 126}$

7 0

4 years ago

How do I solve -15= -3n/5

xenn [34]

Answer:

Step-by-step explanation:

$-\dfrac{3n}{5}=-15\qquad\text{multiply both sides by (-5)}\\\\(-5\!\!\!\!\diagup^1)\left(-\dfrac{3n}{5\!\!\!\!\diagup_1}\right)=(-5)(-15)\\\\3n=75\qquad\text{divide both sides by 3}\\\\n=25$

5 0

3 years ago

Evaluate the function below for x=2. F(x)=2x^3-x^2-5x+6

Advocard [28]

$f(x)=2x^3-x^2-5x+6 \ \ \ \boxed{x=2}\\
\\
f(2)=2*2^3-2^2-5*2+6\\
\\
f(2)=16-4-10+6\\
\\
f(2)=8$

7 0

4 years ago

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