Answer:
n= -3 or in exact form: N= - log27/log3
Step-by-step explanation:
Answer:
your answer is 9
Step-by-step explanation:
Just trust me!
Answer:
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the mean of the Population = 95
Given that the standard deviation of the Population = 5
Let 'X' be the random variable in a normal distribution
Let X⁻ = 96.3
Given that the size 'n' = 84 monitors
<u><em>Step(ii):-</em></u>
<u><em>The Empirical rule</em></u>


Z = 2.383
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = P(Z≥2.383)
= 1- P( Z<2.383)
= 1-( 0.5 -+A(2.38))
= 0.5 - A(2.38)
= 0.5 -0.4913
= 0.0087
<u><em>Final answer:-</em></u>
The probability that the mean monitor life would be greater than 96.3 months in a sample of 84 monitors
P(X⁻ ≥ 96.3) = 0.0087
Answer: 6 km to 22 km !
Step-by-step explanation:
the distances from the school mall to bus station could be, in the worst case, 14+8=22 km apart, and in the best case 14-8=6 km apart
so the range is 6 km to 22 km !
Mary will have saved $87.50
$17.50 per three weeks
x per 15 weeks
17.50 x 5 = $87.50