G^2+2=0,
g^2=-2
g= sqrt-2, not possible.
3g+1=0
3g=-1
g=-1/3
9 cannot be equal to zero for the last one.
7. (150 cal)/(3/4 serving) = 150/1 / 3/4 = 150/1 * 4/3 = 200 cal/serving
Answer:
(-2, -8)
x = -2
y = -8
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define systems</u>
13x - 6y = 22
x = y + 6
<u>Step 2: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 13(y + 6) - 6y = 22
- Distribute 13: 13y + 78 - 6y = 22
- Combine like terms: 7y + 78 = 22
- Isolate <em>y</em> term: 7y = -56
- Isolate <em>y</em>: y = -8
<u>Step 3: Solve for </u><em><u>x</u></em>
- Define original equation: x = y + 6
- Substitute in <em>y</em>: x = -8 + 6
- Add: x = -2
Answer:
- a) $56000
- b) DA = 2, GA = 10
Step-by-step explanation:
<u>Given</u>
- DA = A + B ⇒ $3000
- GA = A + 2B ⇒ $5000
- Number of A = 12
- Number of B = 22
<u>We can see from the equations that</u>
- GA - DA = B ⇒ $2000 and
- A = $1000 and B = $2000 in terms of profit
<u>So greater use of unit B brings greater profit. We don't want any unit is left over, so get this equation.</u>
Is the equation set to indicate use of the units A and B
<u>Solving we get </u>
<u>It this case all the units are used and profit is maximum</u>
- 2*$3000 + 10*$5000 = $56000
- Number of DA = 2
- Number of GA = 10
Answer:
340
Step-by-step explanation:
We can see in the sample that 18/50 people bring lunches to school. If we divide 18 by 50 we get 0.36 now we know that 36% of people bring their lunches in the sample. Now we take that number and multiply it by 942.
0.36*942= 339.12 which we can round to 340
