What is the constant of variation for the quadratic variation? x 2 3 4 5 6 y 24 54 96 150 216

Mathematics

1 answer:

labwork [276]3 years ago

3 0

Y=ax^2

24=4a, a=6

54=9a, a=6

96=16a, a=6

etc

a=6

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2.34 x 10^65 + 9.2 x10^66

vivado [14]

Answer:

9.434 X 10^66

Step-by-step explanation:

2.34 X 10^65 + 9.2 X 10^66 (First, you have to manipulate the exponents to bring them to the same index, i.e. the same power)

We can say that 2.34 X 10^65 = 0.234 X 10^66

Now that the indexes are equivalent, we can proceed to add the two bases together.

0.234 X 10^66 + 9.2 X 10^66

= (0.234 + 9.2) X 10^66

= 9.434 X 10^66

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#82 will give brainliest to best answer!

Fofino [41]

Answer:

$\frac{6}{k-6}$

Step-by-step explanation:

First, we can factor all of the following equations to turn that weird, huge looking thing into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ ÷ $\frac{(k-6)^2}{k(k-6)}$ × $\frac{6(k-10)}{k(k + 6)}$ . We know that division is simply multiplication by the reciprocal, so that whole equation will turn into $\frac{(k+6)(k-6)}{(k-6)(k-10)}$ × $\frac{k(k-6)}{(k-6)^2}$ × $\frac{6(k-10)}{k(k+6)}$ . Now we can cancel out some values if they are both in the numerator and denominator, which will turn that still huge looking thing into $\frac{6}{k-6}$ which is our final answer, as it cannot be simplified further.