A) Demand function
price (x) demand (D(x))
4 540
3.50 810
D - 540 810 - 540
----------- = -----------------
x - 4 3.50 - 4
D - 540
----------- = - 540
x - 4
D - 540 = - 540(x - 4)
D = -540x + 2160 + 540
D = 2700 - 540x
D(x) = 2700 - 540x
Revenue function, R(x)
R(x) = price * demand = x * D(x)
R(x) = x* (2700 - 540x) = 2700x - 540x^2
b) Profit, P(x)
profit = revenue - cost
P(x) = R(x) - 30
P(x) = [2700x - 540x^2] - 30
P(x) = 2700x - 540x^2 - 30
Largest possible profit => vertex of the parabola
vertex of 2700x - 540x^2 - 30
When you calculate the vertex you find x = 5 /2
=> P(x) = 3345
Answer: you should charge a log-on fee of $2.5 to have the largest profit, which is $3345.
Step-by-step explanation:
sin 46°= a/12.8
a = sin46° * 12.8 = 9.20
cos59°=b/16.8
b = cos59°*16.8 = 8.65
Well what you would do is you would first subtract 45 from 325 (325-45) and that would become 280. Then you would divide that number by 8 (the cost of the T-shirt)(280/8) and then your answer would be 35. So the maximum number of T-shirts she will be able to buy is 38. Hope this will help you!
Answer:
d = -2
Step-by-step explanation:
d( 3 ) = ( -6 / d )d
3d = -6
(3d)/3 = (-6)/3
d = -2
