What is the vertex of y = - | x + 3 | + 5

Mathematics

1 answer:

Katyanochek1 [597]3 years ago

7 0

Answer:

vertex = (- 3, 5 )

Step-by-step explanation:

The general form of the absolute value function is

y = a | x - h | + k

where (h, k) are the coordinates of the vertex

Given

y = - | x + 3 | + 5 ← in general form, then

vertex = (- 3, 5 )

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Plz help me with this

Nana76 [90]

This question is not even trying to test your arithmetic. It's just testing
to see whether you know how to read numbers in words properly.

When you read numbers in words, the only time you ever say "and"
is for a decimal point. There are no decimals in this question, so the
"and" is not a part of any numbers.

The question gives you two numbers. The word "and" is the marker
that's BETWEEN them. The two numbers are 1,300 and 950 .

The first thing the question wants you to do is write the numerical
expression for all the words. That's (1300 - 950) / 4 .

The next thing you're supposed to do is"evaluate the expression" ...
find out what number it all boils down to. I don't think you'll have
any trouble with that now.

3 0

3 years ago

Simplify the expression \[\frac{6}{\sqrt{36} + \sqrt{27}} + \frac{6}{\sqrt{27} + \sqrt{18}} + \frac{6}{\sqrt{18} + \sqrt{9}}.\]

Viktor [21]

Answer:

= 18 ( 3 + 2(\sqrt{3} + \sqrt{2} ))

Step-by-step explanation:

$6(\sqrt{36} +\sqrt{27}) + 6(\sqrt{27} +\sqrt{18}) + 6(\sqrt{18} + \sqrt{9} )\\= 6( {6} +\sqrt{9*3}) + 6( \sqrt{9*3} +\sqrt{9*2}) + 6(\sqrt{9*2} + 3 )\\= 6( {6} +3\sqrt{3}) + 6(3\sqrt{3} +3\sqrt{2}) + 6(3\sqrt{2} + 3 )\\=36 + 18\sqrt{3} + 18\sqrt{3} + 18\sqrt{2}+ 18\sqrt{2} + 18\\= 36+18 +18( \sqrt{3}+ \sqrt{3} +\sqrt{2} + \sqrt{2})\\= 54 + 18 (2\sqrt{3} +2\sqrt{2})\\=54 + 36\sqrt{3} + 36\sqrt{2}\\= 18 ( 3 + 2(\sqrt{3} + \sqrt{2} ))$