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mars1129 [50]
3 years ago
13

Fully Factor 3x^2 – 16x + 20

Mathematics
1 answer:
ryzh [129]3 years ago
4 0

Answer:

C. (3x2 - 10) (x - 2)

Step-by-step explanation:

3x^2 - 16x +20

Step 1: Sum = - 16x

Product = 60x^2

Step 2: Find 2 numbers that their sum is -16 and their product is 60. If you do that correctly, then you will get two numbers: 10 and -6

Step 3: Replace -16x with the two numbers found in step 2, then you will have; 3x^2 - 6x - 10x + 20

Step 4: Factorise the equation in step 3, like so;

(3x^2 - 6x)(- 10x + 20)

3x(x - 2) -10(x - 2)

(3x - 10)(x - 2)

To check if the answer is correct, expand the bracket: (3x - 10)(x - 2)

If the bracket is opened properly, you will get 3x^2 - 16x + 20

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5 0
3 years ago
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I do not know how to do this need help
Diano4ka-milaya [45]

Remark

First of all you have to declare the meaning of g(f(x)) After you have done that, you have to make the correct substitution.

Givens

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Discussion

What the given condition g(f(x)) means is that you begin with g(x). Write down g(x) = x^2 -  2

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<u>4x^2 + x + 1</u>

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<u>                         4x^2 + x  + 1</u>

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Answer

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g(f(x)) = 16x^4 + 8x^3 + 9x^2 + 2x - 1

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Step-by-step explanation:

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