6(m-1)=3(3m+5)<br> 6m-6=9m+15

Can anyone help with 3b please

Hoochie [10]

Answer:

2/9

Step-by-step explanation:

2x÷(-6) x=-2/3

put -2/3 in for x

2(-2/3)÷(-6)

that would equal 2/9

I think this is correct I'm sorry if its wrong have a good day!!

6 0

3 years ago

At a height of about 212 meters, One Shell Square is the tallest building in New Orleans. Marlie is creating a scale model of th

alex41 [277]

Answer:

$0.8\ m$

Step-by-step explanation:

In this problem we know that

The scale is equal to

$\frac{1}{250}\frac{m}{m}$

so

by proportion

Find what will be the height of the scale model

$\frac{1}{250}\frac{m}{m}=\frac{x}{212}\frac{m}{m}\\ \\x=212/250\\ \\x= 0.848\ m$

Round to the nearest tenth of a meter

$0.848\ m=0.8\ m$

3 0

4 years ago

Read 2 more answers

Find the explicit formula for the general nth term of the arithmetic sequence described below. Simplify the formula and reduce a

NemiM [27]

Answer:

an = 4/3n - 13/3.

Step-by-step explanation:

The first term is a1,

a24 = a1 + 23d

83/3 = a1 + 4/3* 23

a1 = 83/3 - 92/3

a1 = -9/3 = -3.

So the nth term an = -3 + 4/3(n - 1)

an = -3 + 4/3 n - 4/3

an = 4/3n - 13/3

6 0

4 years ago

Do one of the following, as appropriate. (a) Find the critical value z Subscript alpha divided by 2, (b) find the critical v

babymother [125]

Answer:

We want to construct a confidence interval at 99% of confidence, so then the significance level would be $1-0.99 =0.01$ and the value of $\alpha/2 =0.005$ . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

$z_{\alpha/2}= \pm 2.576$

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

Step-by-step explanation:

For this case we have the following info given:

$\alpha=0.01, n =26, \sigma = 28.9$

We want to construct a confidence interval at 99% of confidence, so then the significance level would be $1-0.99 =0.01$ and the value of $\alpha/2 =0.005$ . And for this case since we know the population deviation is not appropiate use the t distribution since we know the population deviation and the best quantile assuming that the population is normally distributed is given by the z distribution.

And if we find the critical value in the normal standard distribution or excel and we got:

$z_{\alpha/2}= \pm 2.576$

And we can use the following excel code:

"=NORM.INV(0.005,0,1)"

7 0

3 years ago

Select the line segment

daser333 [38]

Answer:

? how does it look to explain it

8 0

4 years ago

6(m-1)=3(3m+5) 6m-6=9m+15