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Mashcka [7]
3 years ago
11

Help plz I need it it’s hard

Mathematics
1 answer:
sveticcg [70]3 years ago
7 0

Answer:

the awnser is 2

Step-by-step explanation:

You might be interested in
Help! It says that I need to determine If both equations represent lines which are parallel, perpendicular, or none...
12345 [234]
    4x + 2y = 8     (1)
    8x + 4y = -4y  (2)

A) Two lines are parallel if they have the same gradient
       - putting both equations into the gradient- intercept form ( y = mx + c                where m is the gradient)
            (1) 4x + 2y = 8
                          2y = 8 - 4x
                            y = -2x + 4
             
            (2) 8x + 4y = -4y
      <span>                    </span>8x = -4y - 4y
                            y = \frac{-8x}{-8}
                            y = -x
   <span>Thus the gradient of the two equations are different and as such          the two lines are not parallel
</span>
B)  When two lines are perpendicular, the product of their gradient is -1
                   m_{1} * m_{2} = p
                                             p = (-2) * (-1)
                                             p =  2
<span>          ∴ the two lines are not perpendicular either.</span>

Thus these lines are SKEWED LINES

4 0
3 years ago
2y = 4x - 8 <br>3x + 2y = 6<br>graph​
Vinvika [58]

Answer:

  see attached

Step-by-step explanation:

I find it convenient to let a graphing calculator draw the graph (attached).

__

If you're drawing the graph by hand, there are a couple of strategies that can be useful.

The first equation is almost in slope-intercept form. Dividing it by 2 will put it in that form:

  y = 2x -4

This tells you that the y-intercept, (0, -4) is a point on the graph, as is the point that is up 2 and right 1 from there: (1, -2). A line through those points completes the graph.

__

The second equation is in standard form, so the x- and y-intercepts are easily found. One way to do that is to divide by the constant on the right to get ...

  x/2 +y/3 = 1

The denominators of the x-term and the y-term are the x-intercept and the y-intercept, respectively. If that is too mind-bending, you can simply set x=0 to find the y-intercept:

  0 +2y = 6

  y = 6/2 = 3

and set y=0 to find the x-intercept

  3x +0 = 6

  x = 6/3 = 2

Plot the intercepts and draw the line through them for the graph of this equation.

___

Here, we have suggested graphing strategies that don't involve a lot of manipulation of the equations. The idea is to get there as quickly as possible with a minimum of mistakes.

8 0
3 years ago
Hector works 12 hours per week at a part-time
rewona [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
1 2 3 4 5 6 7 8 9 10
kirza4 [7]
Yes so i do need to doing the times and multipics then get a fraction then u will get tot eh answer
6 0
3 years ago
The maximum value of the function: f(x)= -5 x ^2 +30x-200 is?
VARVARA [1.3K]

Answer:

\displaystyle    - 155

Step-by-step explanation:

we are given a quadratic function

\displaystyle f(x) =  - 5 {x}^{2}  + 30x - 200

we want to figure out the minimum value of the function

to do so we need to figure out the minimum value of x in the case we can consider the following formula:

\displaystyle x _{ \rm  min} =  \frac{ - b}{2a}

the given function is in the standard form i.e

\displaystyle f(x) = a {x}^{2}  + bx + c

so we acquire:

  • b=30
  • a=-5

thus substitute:

\displaystyle x _{ \rm  min} =  \frac{ - 30}{2. - 5}

simplify multiplication:

\displaystyle x _{ \rm  min} =  \frac{ - 30}{ - 10}

simply division:

\displaystyle x _{ \rm  min} =  3

plug in the value of minimum x to the given function:

\displaystyle f (3)=  - 5 {(3)}^{2}  + 30.3 - 200

simplify square:

\displaystyle f (3)=  - 5 {(9)}^{}  + 30.3 - 200

simplify multiplication:

\displaystyle f (3)=  - 45  + 90- 200

simplify:

\displaystyle f (3)=   - 155

hence,

the minimum value of the function is -155

5 0
2 years ago
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