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jolli1 [7]
4 years ago
8

Differenciate by first principles f(x) = 4x²-4x-3

Mathematics
2 answers:
Stells [14]4 years ago
6 0
f'(x)= \lim_{h \to 0}  \frac{f(x+h)-f(x)}{h} \\\\-----------------\\f(x)=4x^2-4x-3\\\\f'(x)= \lim_{h \to 0}  \frac{4(x+h)^2-4(x+h)-3-(4x^2-4x-3)}{h}=\\\\=\lim_{h \to 0}  \frac{4(x^2+2xh+h^2)-4x-4h-3-4x^2+4x+3}{h}=\\\\=\lim_{h \to 0}  \frac{4x^2+8xh+4h^2-4x-4h-3-4x^2+4x+3}{h}=\\\\=\lim_{h \to 0}  \frac{8xh+4h^2-4h}{h}=\lim_{h \to 0} (8x+4h- 4)=8x+4\cdot0-4=8x-4\\\\f'(x)=8x-4
zysi [14]4 years ago
3 0
f(x) = 4x^2-4x-3\\
f'(x)=\lim_{h\to0}\frac{f(x+h)-f(x)}{h}\\
f'(x)=\lim_{h\to0}\frac{4(x+h)^2-4(x+h)-3-(4x^2-4x-3)}{h}\\
f'(x)=\lim_{h\to0}\frac{4(x^2+2hx+h^2)-4x-4h-3-4x^2+4x+3}{h}\\
f'(x)=\lim_{h\to0}\frac{4x^2+8hx+4h^2-4h-4x^2}{h}\\
f'(x)=\lim_{h\to0}\frac{8hx+4h^2-4h}{h}\\
f'(x)=\lim_{h\to0}{8x+4h-4}\\
f'(x)=8x+4\cdot0-4\\
f'(x)=8x-4\\
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4 years ago
Determine the singular points of the following differential equation and classify each singular point as regular or irregular.
anygoal [31]
Let be
p(x)=<span>(x^{2} -1
q(x)=</span><span>3(x+1)
r(x)=1
the three coefficients of the equation
a is a singular point of the equation if   lim p(x) =0
                                                              x------>a 
so let's find a
</span> lim p(x) = lim x²-1=a²-1=0
  x------>a    x------>a 
a²-1=0 implies  a=+ or -1

so the sigular points are a= -1 or a=1

case 1
for a= -1
lim (x-(-1)) q(x)/p(x)=lim (x+1) 3(x+1)/x²-1=lim3(x+1)/x-1= 0/-2=0
x------> -1                  x------> -1                    x------> -1
lim (x-(-1))²  r(x)/p(x)= lim(x+1)²/x²-1= 0/-2=0
x------> -1                    x------> -1

lim (x-(-1)) q(x)/p(x) and lim (x-(-1))²  r(x)/p(x) are finite so  -1 is regular 
 x------> -1                        x------> -1
singular point

case 2
a=1
lim (x-1)) q(x)/p(x)=lim (x-1) 3(x+1)/x²-1=lim3(x+1)/x+1= 3
x------> 1                  x------> 1                    x------> 1
lim (x-1))²  r(x)/p(x)= lim(x-1)²/x²-1= =0
x------> 1                    x------> 1

1 is also a regular singular point


5 0
3 years ago
What are the first four terms of the sequence an=n2+4
Igoryamba

Step-by-step explanation:

Given formula

an = n² + 4

Now the first four terms of the sequence are

a1 = 1² + 4 = 5

a2 = 2² + 4 = 4 + 4 = 8

a3 = 3² + 4 = 9 + 4 = 13

a4 = 4² + 4 = 16 + 4 = 20

The terms are

5 , 8 , 13 and 20.

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