<h2>
Speed of plane = 1110 kmph</h2><h2>
Speed of wind = 150 kmph</h2>
Step-by-step explanation:
Let the speed of plane be p and speed of wind be w.
Flying against the wind, an airplane travels 5760 kilometers in 6 hours.
Here
Speed = (p-w) kmph
Time = 6 hours
Distance = 5760 kmph
Distance = Speed x Time
5760 = (p-w) x 6
p-w = 960 -----eqn 1
Flying with the wind, the same plane travels 6300 kilometers in 5 hours.
Here
Speed = (p+w) kmph
Time = 5 hours
Distance = 6300 kmph
Distance = Speed x Time
6300 = (p+w) x 5
p+w = 1260 -----eqn 2
eqn 1 + eqn 2
p-w + p +w = 960 + 1260
2p = 2220
p = 1110 kmph
Substituting in eqn 2
1110 + w = 1260
w = 150 kmph
Speed of plane = 1110 kmph
Speed of wind = 150 kmph
Distribution method
(2x+6)(2x-6)
=4x^2-12x+12x-36
=4x^2-36
I think the answer is 3, -8/2 / 6/-3 .... then you flip and multiply to get to -8/2 x -3/6 which = 24/8 which is equal to 3
