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3 years ago

Need help with this please

Mathematics

1 answer:

Sav [38]3 years ago

4 0

Your going to have to use the distance formula for these questions which is the square root of (x sub 2 - x sub 1) + (y sub 2 - y sub 1). For number 1 your coordinates are (-5,5) and (1,-2). Substituting these values into the formula your answer for number 1 is 9.2.

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Francis works at Carlos Bakery and is making cookie trays. She has 48 chocolate chip cookies, 64 rainbow cookies, and 120 oatmea

amm1812

The number of cookies and trays are illustrations of greatest common factors.

The number of trays is 8
6 chocolate chips, 8 rainbows and 15 oatmeal cookies would fit each tray

The given parameters are:

$\mathbf{Chocolate\ chip=48}$

$\mathbf{Rainbow=64}$

$\mathbf{Oatmeal=120}$

(a) The number of trays

To do this, we simply calculate the greatest common factor of 48, 64 and 120

Factorize the numbers, as follows:

$\mathbf{48 = 2 \times 2 \times 2 \times 2 \times 3}$

$\mathbf{64 = 2 \times 2 \times 2 \times 2 \times 2 \times 2}$

$\mathbf{120 = 2 \times 2 \times 2 \times 3 \times 5}$

So, the GCF is:

$\mathbf{GCF= 2 \times 2 \times 2}$

$\mathbf{GCF= 8}$

Hence, the number of tray is 8

(b) The number of each type of cookie

We have

$\mathbf{Chocolate\ chip=48}$

$\mathbf{Rainbow=64}$

$\mathbf{Oatmeal=120}$

Divide each cookie by the number of trays

So, we have:

$\mathbf{Chocolate\ chip = \frac{48}{8} = 6}$

$\mathbf{Rainbow = \frac{64}{8} = 8}$

$\mathbf{Oatmeal = \frac{150}{8} = 15}$

Hence, 6 chocolate chips, 8 rainbows and 15 oatmeal cookies would fit each tray

Read more about greatest common factors at:

brainly.com/question/11221202

4 0

2 years ago

A bag contains 48 balls

FrozenT [24]

Answer:

25 Balls

Step-by-step explanation:

6 0

3 years ago

Solve the inequality 4b

Mnenie [13.5K]

Could you maybe provide us with a better explantion or picture?

4 0

3 years ago

Cound someone please help me on this, I'm stuck.

Katyanochek1 [597]

Negative exponents work like this:

$a^{-b}=\dfrac{1}{a^b}$

So, in order to evaluate a negative exponent, you simply have to invert the base, and then raise to the positive equivalent of the exponent.

As an example, here are the first three exercises:

$8^{-3}=\dfrac{1}{8^3}=\dfrac{1}{512}$

$(-4)^{-5}=\dfrac{1}{(-4)^5}=-\dfrac{1}{1024}$

$2k^{-4}=\dfrac{2}{k^4}$

You can work out the rest applying this logic.

5 0

3 years ago

What else would need to be congruent to show that abc = xyz by asa

pochemuha

Since you're working with the ASA postulate, you're looking to show congruence of the angles at either end of a side. You're given side AC and angle A as congruent with their counterparts. Obviously, you also need to show congruence of angle C with its counterpart, angle Z.

selection B is appropriate

6 0

3 years ago