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3 years ago

Find the length of side xx to the nearest tenth. 30° 60° x 9

Mathematics

1 answer:

otez555 [7]3 years ago

4 0

Answer:

yes I am the only one that has a lil before I go to

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The current average property value is two-sevenths more than last year’s average value. What was last year’s average property va

Ilya [14]

Answer:

$63350$

Step-by-step explanation:

Given that the current average property value is two-sevenths more than last year’s average value.

Let x be the last year's average property

Then we have as per the given information this year property value

= $x+\frac{2}{7} x$

Equate this to

$x+\frac{2}{7} x=81450\\9x = 7(81450)\\x = 7(9050)\\x= 63350$

6 0

3 years ago

If y varies inversely as x and y=16 when x=4, find y when x=3

iren [92.7K]

Answer:

21.33 to nearest hundredth

Step-by-step explanation:

Inverse Variation is y = k / x where k is a constant.

Plug in the given values to find k:-

16 = k/4

k = 4*16 = 64 so the equation of variation is y = 64/x.

So when x = 3, y = 64/3 = = 21.33 to nearest hundredth.

6 0

4 years ago

Lim as x->ln2 of ((e^3x)-8)/((e^2x)-4)

andriy [413]

X ⇒ ln (2)

e^3 x - 8/e^2 x - 4

7 0

3 years ago

Serena has 3 3/5sq meters of wrapping paper for presents. Her grandmother has 1 1/2sq meters of wrapping paper. How much wrappin

levacccp [35]

Answer:

Total wrapping papers Serena and her grandmother = 51/10

Step-by-step explanation:

Serena's wrapping paper for parents:

$3\frac{3}{5}=\frac{18}{5}$ sq meters

Grandmother's wrapping paper:

$1\frac{1}{2}=\frac{3}{2}$ sq meters

In order to determine the combined wrapping papers for both Serena and grandmother, all we need is to add both.

i.e.

Total papers = Serena's wrapping paper + Grandmother's wrapping paper

$=\frac{18}{5}+\frac{3}{2}$

$=\frac{36}{10}+\frac{15}{10}$

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{c}+\frac{b}{c}=\frac{a+b}{c}$

$=\frac{36+15}{10}$

$=\frac{51}{10}$

Therefore, total wrapping papers Serena and her grandmother = 51/10

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3 years ago

Polly and Percy were sharing a bag ofjelly beans. The bag contained 52 orange, 63 lime, 72 cherry, 28 lemon and 65 grape. If Pol

wel

Answer:

Step-by-step explanation:

6 0

3 years ago