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blagie [28]
2 years ago
11

Find the length of side xx to the nearest tenth. 30° 60° x 9

Mathematics
1 answer:
otez555 [7]2 years ago
4 0

Answer:

yes I am the only one that has a lil before I go to

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The back of Tom's property is a creek. Tom would like to enclose a rectangular area, using the creek as one side and fencing
Anna71 [15]

9514 1404 393

Answer:

  1250 square feet

Step-by-step explanation:

If x is the length of the side perpendicular to the creek, then the third side is (100 -2x) = 2(50 -x). The area is the product of length and width:

  A = x(2)(50-x)

We observe that this is a quadratic function with zeros at x=0 and x=50. The vertex (maximum) of a quadratic function is on the line of symmetry, halfway between the zeros. The value of x there is (0 +50)/2 = 25.

Then the maximum area is ...

  A = (25)(2)(50 -25) = 1250 . . . . square feet

_____

<em>Additional comment</em>

Note that half the length of the fence is used in one direction (parallel to the creek), and half is used in the other direction (perpendicular to the creek). This 50/50 split is the generic solution to all sorts of rectangular corral problems, with or without a creek, with or without internal partitions.

Half the fence is perpendicular to the other half. (If the costs are different in different directions, then the cost is what is split 50/50.)

8 0
2 years ago
Diana's spends 0. 8 hours per day at the pool if she goes to the pool for two days one week how many total hours does Diana spen
vesna_86 [32]
Multiply 0.8 two times. ( 0.8 • 3 ) This is because the problem said only for TWO days during one week. As well as she spend 0.8 for each day. The answer of this problem is 2.4
3 0
3 years ago
The value of y varies directly with x. When y = 75, x = ½ . What is the value of y when x is 2 ¼ ? A. 168.75 C. 66.67 B. 16.67 D
lora16 [44]

Answer:

Step-by-step explanation:

The value of y varies directly with x. When y = 75, x = ½ . What is the value of y when x is 2 ¼ ? A. 168.75 C. 66.67 B. 16.67 D. 337.5

y ∝x

y = kx

k = y/x

8 0
2 years ago
A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 98m long and 76m wide. F
Vsevolod [243]
Without the image, I assume the two semicircles are on each end of the rectangle.

Rectangle; A = lw
A = 98 x 76
A = 7,448 square meters

Put the two semicircles together to form a circle; A = π2^{2}
A = (3.14)(76^{2})
A = 3.14 x 76 = 5,776 square meters

7,448 + 5,776 = 13,224 square meters
5 0
2 years ago
Please help ASAP. Will give brainliest!
Mazyrski [523]
The anwser should be c
5 0
3 years ago
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