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4 years ago

Which shows the equation below.....

Mathematics

2 answers:

sladkih [1.3K]4 years ago

8 0

Option A is your answer.

Subtract 3 from both sides to get zero on the right side of the equal sign.

8 - 3 = 5.

So that becomes your constant term in the equation.

zimovet [89]4 years ago

3 0

Subtract 3 from both sides to get the equation equal to 0.

You would get: x^2+6x+5, which is A.

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sergejj [24]

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3 years ago

2/3 (12x-9) i need help on this

schepotkina [342]

Answer:

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Step-by-step explanation:

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3 years ago

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What is the reciprocal of 1 and 1/9

podryga [215]

Answer:

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3 years ago

In triangle ΔABC, ∠C is a right angle and CD is the height to

Zina [86]

Answer:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

Step-by-step explanation:

The triangles are drawn below.

CD is perpendicular to AB as CD is height to AB.

Therefore, angles $m\angle CDB=m\angle CDA=90$ °

So, triangles ΔCBD and ΔCAD are right angled triangles.

Now, from the right angled triangle ΔABC,

$m\angle A+m\angle B =90\\\alpha+m\angle B=90\\m\angle B=90-\alpha$

From ΔCBD,

$m\angle CBD$ is same as $m\angle B$ .

So, $m\angle CBD=90-\alpha$

$m\angle BCD+m\angle BDC =90\\m\angle BCD+90-\alpha=90\\m\angle BCD=\alpha$

Now, from ΔCAD,

$m\angle CAD$ is same as $m\angle A$

So, $m\angle CAD=\alpha$

$m\angle CAD+m\angle ACD =90\\\alpha+m\angle ACD=90\\m\angle ACD=90-\alpha$

Hence, the unknown angles of both the triangles are:

$m\angle CDB=90\\m\angle CBD=90-\alpha\\m\angle BCD=\alpha\\\\m\angle CDA=90\\m\angle CAD=\alpha\\m\angle ACD=90-\alpha$

5 0

3 years ago

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ElenaW [278]

Answer:

t ≥ -12

Step-by-step explanation:

Divide the inequality by the coefficient of t. Because that value is negative, the sign gets reversed.

(-4t)/(-4) ≥ (48)/(-4)

t ≥ -12

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4 years ago