Answer:
$899.15
0.85(1199) - 120
Step-by-step explanation:
To find the purchase total, multiply the price by the percent paid and subtract the certificate.
The store offers a 15% discount. This means you pay 85% of the price. So the discounted price is 0.85(1199) = 1019.15
Subtract the certificate 1019.15 - 120 = 899.15
The composite function is 0.85(1199) - 120.
For this case we have the following system of equations:

We multiply the first equation by -1:

We have the following equivalent system:

We add the equations:

Equality is not fulfilled, so the system of equations has no solution.
Answer:
Option C
To find the z-score for a weight of 196 oz., use

A table for the cumulative distribution function for the normal distribution (see picture) gives the area 0.9772 BELOW the z-score z = 2. Carl is wondering about the percentage of boxes with weights ABOVE z = 2. The total area under the normal curve is 1, so subtract .9772 from 1.0000.
1.0000 - .9772 = 0.0228, so about 2.3% of the boxes will weigh more than 196 oz.
So there are x girls and x-4 boys and together they make 28:
x+x-4=28
2x-4=28
2x=32
x=16
so there are 16 girls and 12 boys.
the ratio is then 16:12, or we can simplify (by dividing both sides by 4): 4:3
so the best answer is 4:3.
6(-3)-1-51+131=
-18-1-51+131=
-70+131=61