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Mnenie [13.5K]
3 years ago
10

I need help I have a test tomorrow and this is all I am being tested on and I dont get it

Mathematics
1 answer:
Bond [772]3 years ago
3 0
In figure 1 there are 7 squares, in figure 2 there are 10 squares, figure 3 there are 13 squares. in each figure you are just adding 3. (try to find the patterns.) The equation representing the figures is x+3=y.
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Someone please help meee
slamgirl [31]
Use the formula:
Y-yo=m(x-xo)
8 0
3 years ago
Can someone please help me with this
KatRina [158]

Answer:

13)5m-10

14)8y+16

15)-3m-12

16)a²+3a

17)h²-2h

18)2m²+8m

19)-2z+16

20)-4x²+40x

21) 12x and 60

22)x and 4

7 0
3 years ago
Read 2 more answers
HELP PLEASEEEEEEEE!!!!!!!!!!!!!!!!!
mariarad [96]
Plus or minus 3. (The 1st answer)

x^2 means (-3*-3) which equals 9

x^2 means (3838) which also equals 9

6*9=54

7 0
3 years ago
Read 2 more answers
There are 30 balls numbered 1-30 in a bag. One is randomly selected 12 times. What is the probability of getting a prime number
Sliva [168]

Answer: The probability of getting a prime number exactly five times = 0.1908

Step-by-step explanation:

Prime numbers from 1 to 30 are 2,3,5,7,11, 13, 17, 19, 23, 29.

The probability of getting a prime number p= \dfrac{10}{30}=\dfrac13

Number of trials n = 12

Binomial probability formula:

P(X=x) = \ ^nC_x p^x(1-p)^{n-x}

, where x= number of successes

n= number of trials.

x = Number of successes

p= probability of getting one success.

The probability of getting a prime number exactly five times:

P(X=5)=\ ^{12}C_5(\frac13)^5(1-\frac13)^{7}

=\frac{12!}{5!7!}(\frac1{243})(\frac{128}{2187})\\\\=0.1908

Hence, the probability of getting a prime number exactly five times = 0.1908

4 0
3 years ago
Point C(3.6, -0.4) divides in the ratio 3 : 2. If the coordinates of A are (-6, 5), the coordinates of point B are . If point D
polet [3.4K]
Given:
A has coordinates (-6,5)
C has coordinates (3.6,-0.4).
C divides AB in the ratio 3:2.

Refer to the diagram shown below.
The coordinates of B are determined by
\frac{3.6-(-6)}{x-(-6)} = \frac{3}{3+2} \\ \frac{9.6}{x+6} = \frac{3}{5} \\ 3(x+6) = 48 \\ 3x +18=48 \\ x=30/3=10
Also,
\frac{5-(-0.4)}{5-y} = \frac{3}{5} \\ 3(5-y) = 27 \\ 15-3y=27 \\ y= \frac{12}{-3} =-4

Answer:
The coordinates of B are (10,-4).

Now, we know the coordinates of line segment AB as A (-6, 5) and B (10,-4).
D (x,y) divides AB in the ratio 4:5.
Therefore
\frac{x-(-6)}{10-(-6)} = \frac{4}{4+5} \\ \frac{x+6}{16} = \frac{4}{9} \\ 9(x+6)=64 \\ 9x+54=64 \\ x=1.11
Also,
\frac{5-y}{5-(-4)} = \frac{4}{9}  \\ 5-y = 4 \\ y = 1

Answer:
The coordinates of D are (1.11, 1)

4 0
4 years ago
Read 2 more answers
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