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valkas [14]
3 years ago
14

What is the value of the function at x=−2? A) y=−2 B) y = 0 C) y = 2 D) y = 3

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0
It’s A for the value of the function u asking for
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The top of angies ladder is resting against the side of her house 22 feet above the ground.If the base of the ladder is 5 feet f
Andrews [41]

Answer:

Step-by-step explanation:

The attached diagram shows the triangle ABC formed by the ladder with the wall of the house.

Triangle ABC is a right angle triangle. It has a 90 degree angle. The length of the ladder forms the hypotenuse(AC)of the triangle. This length can be determined by applying Pythagoras theorem

Hypotenuse^2 = opposite ^2 + adjacent^2

AC^2 = 22^2 + 5^2

AC^2 = 484 + 25 = 509

AC = √509

AC = 22.56

The slope of the ladder is

(change in y)/(change in x)

Slope = 22/5 = 4.4

3 0
3 years ago
Which answer would it be
ziro4ka [17]

Answer:

D

Step-by-step explanation:

usually anything with 11 on the numerator is a repeating decimal and the 0.37 is closest to 36.

so by guessing you know is D

5 0
2 years ago
Read 2 more answers
Please help me with this question! Will give brainliest!
MissTica

Answer:

D) 2/3 x - 8

E) -4x + 11

Step-by-step explanation:

y ∈ R | -∞ < y < ∞ just means that the range for y is all real numbers in a function. For y to be all real numbers, the function, when graphed, has to have no top or bottom limit. The only graphs without top or bottom limits are D and E.

A has a bottom limit

B has a bottom limit

C has a top limit

4 0
3 years ago
Question 3 Please. I'm really stuck :(
Stells [14]
Let ∠RTS=∠RST = a (say)
 ∠QUA=∠QSU= b(say)
then we know , at point S, a+40+b=180. so, a+b=140 we'll use this later.

consider trianglePQR, ∠P+∠Q+∠R=180
i.e.P+(180-2b)+(180-2a)=180
P+180+180-2(a+b)=180 ⇒P+180-2(a+b)=0 ⇒P=2(140)- 180=280-180=100
hence,answer is E
7 0
2 years ago
Read 2 more answers
x2 + y2 − 4x + 12y − 20 = 0 (x − 6)2 + (y − 4)2 = 56 x2 + y2 + 6x − 8y − 10 = 0 (x − 2)2 + (y + 6)2 = 60 3x2 + 3y2 + 12x + 18y −
snow_tiger [21]
For this case, what we must do is fill squares in all the expressions until we find the correct result.
 We have then:
 
 x2 + y2 − 4x + 12y − 20 = 0 x2 + y2  − 4x + 12y = 20
 x2  − 4x + y2 + 12y = 20
 x2  − 4x + (12/2)^2 + y2 + 12y  + (-4/2)^2 = 20 + (12/2)^2 + (-4/2)^2
 x2  − 4x + (6)^2 + y2 + 12y  + (-2)^2 = 20 + (6)^2 + (-2)^2
 x2  − 4x + 36 + y2 + 12y  + 4 = 20 + 36 + 4
 (x − 2)2 + (y + 6)2 = 60 

 
3x2 + 3y2 + 12x + 18y − 15 = 0 
 
x2 + y2 + 4x + 6y − 5 = 0 
 x2 + y2 + 4x + 6y  = 5 
 x2  + 4x + (4/2)^2 + y2 + 6y + (6/2)^2 = 5 + (4/2)^2 + (6/2)^2 
 x2  + 4x + (2)^2 + y2 + 6y + (3)^2 = 5 + (2)^2 + (3)^2 
 x2  + 4x + 4 + y2 + 6y + 9 = 5 + 4 + 9 
 (x + 2)2 + (y + 3)2 = 18 

 2x2 + 2y2 − 24x − 16y − 8 = 0
 x2 + y2 − 12x − 8y − 4 = 0
 x2 + y2 − 12x − 8y = 4 
 x2 − 12x + (-12/2)^2 + y2 − 8y + (-8/2)^2 = 4 + (-12/2)^2 + (-8/2)^2
 x2 − 12x + (-6)^2 + y2 − 8y + (-4)^2 = 4 + (-6)^2 + (-4)^2
 x2 − 12x + 36 + y2 − 8y + 16 = 4 + 36 + 16
 (x − 6)2 + (y − 4)2 = 56 

 x2 + y2 + 2x − 12y − 9 = 0
 x2 + y2  + 2x - 12y = 9
 x2  + 2x + y2 - 12y = 9
 x2  + 2x + (2/2)^2 + y2 - 12y  + (-12/2)^2 = 9 + (2/2)^2 + (-12/2)^2
 x2  + 2x + (1)^2 + y2 - 12y  + (-6)^2 = 9 + (1)^2 + (-6)^2
 x2  + 2x + 1 + y2 - 12y  + 36 = 9 + 1 + 36
 (x + 1)2 + (y − 6)2 = 46
7 0
3 years ago
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