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Simora [160]
3 years ago
7

Three swimmers competed in a 50 m freestyle race. A description of their swimming speeds is given. Order the swimmers from first

to third place.
1) Terrance swam faster than mike

2) Nathan swam 50 meters in 32 seconds

3) Mike swam 50 meters in 28 seconds
Mathematics
2 answers:
sleet_krkn [62]3 years ago
6 0
Terrance mike Nathan
alexandr1967 [171]3 years ago
3 0

Answer:

terrance then mike then nathan

Step-by-step explanation:

You might be interested in
Wayne has 303 marbles. If he keeps 123 of the marbles and gives the rest of the marbles equally to 3 friends, about how many mar
alekssr [168]

Answer:

60 marbles to each friend, 180 marbles total.

Step-by-step explanation:

303-123= 180

180/3= 60

5 0
3 years ago
In a random sample of 535 people 65% said they like cookies with chocolate chips 37% like cookies with peanut butter chips. 25%
Leokris [45]
<h3>The probability that a randomly selected person likes cookies with chocolate or peanut butter chips is 0.77.</h3>

Step-by-step explanation:

Here, the total sample of people has total  535 people.

The percentage of people liking chocolate chip cookies  =  65%

Now, 65% of 535   = \frac{65}{100} \times 535 = 347.75 \approx 348

⇒ 348 people in total like chocolate chip cookies.

⇒ n(C)  = 348

The percentage of people liking peanut butter chip cookies  =  37%

Now, 37% of 535   = \frac{37}{100} \times 535 = 197.95 \approx 198

⇒ 198 people in total like peanut butter chip cookies.

⇒ n(B)  = 198

Percentage of people liking both chocolate &peanut butter chips = 25%  

Now, 25% of 535   = \frac{25}{100} \times 535 =133.75 \approx 134

⇒ 134 people in total like both chocolate &peanut butter chips

⇒ n(C ∩ B )  = 134

Now, n( C U B)  = N(C) + n(B) - n(C ∩ B )

                           = 348 + 198 - 134  = 412

P( person likes cookies with chocolate or peanut butter chips)  

= \frac{\textrm{person likes cookies with chocolate or peanut butter chips}}{\textrm{Total People}}  = \frac{412}{535}  = 0.77

Hence, the probability that a randomly selected person likes cookies with chocolate or peanut butter chips is 0.77.

6 0
3 years ago
Make tables to find the solution to 2^−x = 4^x + 3. Take the integer values of x only between −3 and 3.
Kryger [21]
X    2^(-x)    4^(x+3)

-3    8          1

-2    4          4

-1    0        16

0      1        64

1      0.5      256

2      0.25    1024

3      0.125  4096

The solution is x = -2 because both functions return the same value, i.e. 4.
3 0
3 years ago
The Acculturation Rating Scale for Mexican Americans (ARSMA) is a psychological test that measures the degree to which Mexican A
aleksandr82 [10.1K]

Answer:

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

The distribution of ARSMA scores in a population used to develop the test is approximately Normal with mean 3.0 and standard deviation 0.8.

This means that \mu = 3, \sigma = 0.8

What proportion of the population used to develop the test has scores below 1.7?

This is the pvalue of Z when X = 1.7. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.7 - 3}{0.8}

Z = -1.63

Z = -1.63 has a pvalue of 0.063

The proportion of the population used to develop the test that has scores below 1.7 is 0.063.

Between 1.7 and 2.1?

This is the pvalue of Z when X = 2.1 subtracted by the pvalue of Z when X = 1.7.

X = 2.1

Z = \frac{X - \mu}{\sigma}

Z = \frac{2.1 - 3}{0.8}

Z = -1.13

Z = -1.13 has a pvalue of 0.1292

X = 1.7

Z = \frac{X - \mu}{\sigma}

Z = \frac{1.7 - 3}{0.8}

Z = -1.63

Z = -1.63 has a pvalue of 0.063

0.1292 - 0.063 = 0.0662

The proportion of the population used to develop the test that has scores between 1.7 and 2.1 is 0.0662.

3 0
3 years ago
The largest number in a series of consecutive even integers is w. If the number of integers is n, what is the smallest number in
Reika [66]

Answer:

  C.  w–2(n–1)

Step-by-step explanation:

One way to think of this is that the smallest is the n-th term of an arithmetic sequence with w as the first term and -2 as the common difference. The formula for the n-th term is ...

  an = a1 + d(n -1)

Filling in the given values, we have ...

  smallest number = w -2(n -1) . . . . . matches choice C

5 0
3 years ago
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