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Allisa [31]
4 years ago
6

Algebraic fractions must have a variable in the numerator and denominator.

Mathematics
2 answers:
irga5000 [103]4 years ago
8 0
I dont know whether you wanted a true or false answer, but if you did, that statement would be correct/true. Hope this helped!
vova2212 [387]4 years ago
3 0

Answer:

False

Step-by-step explanation:

It must have a variable in the numerator OR denominator.

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Which ordered pair in the form (a, b) is a solution of this equation?
Evgen [1.6K]

3a - 4b = 21


check (-2 , -3)


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6 does not = 21  so NO


check (0 , 7)


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check (-3 , -2)


3(-3) -4(-2) =21


-9 +8  = 21


1 does not = 21  so NO


check (7 , 0)


3(7) -4(0) =21


21  = 21

Choice D

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3 years ago
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zhenek [66]
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Also note how 707,747 rounds to 708,000 when rounding to 3 significant figures.

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