Answer:
P = 6200 / (1 + 5.2e^(0.0013t))
increases the fastest
Step-by-step explanation:
dP/dt = 0.0013 P (1 − P/6200)
Separate the variables.
dP / [P (1 − P/6200)] = 0.0013 dt
Multiply the left side by 6200 / 6200.
6200 dP / [P (6200 − P)] = 0.0013 dt
Factor P from the denominator.
6200 dP / [P² (6200/P − 1)] = 0.0013 dt
(6200/P²) dP / (6200/P − 1) = 0.0013 dt
Integrate.
ln│6200/P − 1│= 0.0013t + C
Solve for P.
6200/P − 1 = Ce^(0.0013t)
6200/P = 1 + Ce^(0.0013t)
P = 6200 / (1 + Ce^(0.0013t))
At t = 0, P = 1000.
1000 = 6200 / (1 + C)
1 + C = 6.2
C = 5.2
P = 6200 / (1 + 5.2e^(0.0013t))
You need to change the exponent from negative to positive.
The inflection points are where the population increases the fastest.
Answer:
a) The value of the Annual Payment is A=$17,258.80
b) Is the picture in the attachment file
c) As you can see it in the picture with each payment, balance comes down, due it is the interest base, Interest portion comes down too.
Step-by-step explanation:
Hi
a) First of all, we are going to list the Knowns: 
, 
% and 
, Then we can use 
. So this is the value of the Annual Payment
Answer:
15 remainder 3
Step-by-step explanation:
It is complicated how I did it so yeah
Answer:
If the blue radius below is perpendicular to the green chord and the segment
AB is 6 unit long what is the Length of the chord 12 unit.
