i can't really see the image but i'm sure it's pretty cool (:
Answer:
option b is the answer of your question
<h3>Answer:</h3>
x = 3
<h3>Explanation:</h3>
The product of the lengths of segments from the intersection point to the circle is the same for both secants.
... 1×6 = 2×x
... 6/2 = x = 3 . . . . . divide by 2
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<em>Comment on secant geometry</em>
Interestingly, this relation is true whether the point of intersection of the secants is inside the circle or outside.
When it is outside, the product is of the distance to the near intersection with the circle and the distance to the far intersection with the circle.
Plug it in your y= screen of your graphing calculator and hit 2nd and then graph. it will give u a table of values
If r(x)= 11x, and c(x)=6x +20, then just put that into the equation.
So instead of p(x) = r(x) - c(x)
I would be p(x) = 11x - 6x + 20
Now solve.
p(x) = 5x + 20 is your final answer, so A.
