Answer: 22 meters
<u>Step-by-step explanation:</u>
Draw a picture of a right triangle and label the height as 30 meters and the hypotenuse as 37 meters. Use the Pythagorean Theorem to find the base (the length of the shadow).
a² + b² = c²
x² + 30² = 37²
x² = 37² - 30²
x² = 1369 - 900
x² = 469
√x² = √469
x = 21.656
x ≈ 22
I can't really measure the angles. I can tell you what they look like they'd be. There are three reasons why not.
1. The paper is slightly bulged where your hand is
2. The circle is slightly distorted by the camera. This is not that critical.
3. It is very hard to measure on a computer screen.
There is nothing you could do to make it any better. In fact, given what you had to do, this is a pretty good representation.
The Three angles -- Question 22
Using the crudest tools you could imagine, I measured the angle where you have written two 90s between the arms as 132°. That angle opens towards the bottom of the page.
The angle that you have called 95 degrees is actually pretty close. I think you read the upper set of numbers on the protractor when you should have been reading the lower set. I make it 89, but I'll bet it is intended to be 90 degrees.
The third angle on your right is the same as the first one. It comes in at about 132° using my tools again.
Question 23
I can help you with this. When you are asked to make an equation, you have to use an equal sign somewhere.
The sum of the three angles should be 360° I'm going to create an error term because I'm almost sure what I measured won't make 360. All circles when you make angles from any point inside them should make angles that add up to 360° when measured with a protractor if the rays of the angles all start from the same point. [If you don't know what a ray is, call it "the arms of the angles"].
So let's create the equation.
Angle1 + angle2 + angle3 + E = 360°
Angle1 = 89°
Angle2 = 132°
Angle3 = 132°
E is the error that represents the amount away from 360. Your teacher doesn't expect you to get this or to set it into your equation. The main thing you were supposed to do is add up the angles as you tried to do and state what your total was. This is what was expected.
Total = angle1 + angle2 + angle3
Total = 89 + 132 + 132 = 353. My error is 7° too little. So in my equation E = 7°
What to do
Somebody had to mark this with that green felt. You have a teacher. Go to the teacher and ask to be shown how to read the protractor if that person knows. You just need a bit of help. If the teacher cannot tell you, go to someone in your class who knows about that sort of thing and ask them. You're pretty close to getting it.
Method A: 7.6666.... = 7 + 0.6666... = 7 + 2/3 = 21/3 + 2/3 = 23/3
Method B: 10(7.666...) - 1(7.666...) = 76.666... - 7.666... = 69.000...
(10 - 1)(7.666...) = 69
7.666... = 69/9 = 23/3
Easy first cover kilograms into grams 1kg=1000g. resulting in 10,000g dividing that by the weight of the oranges getting 10,000/200=50 so the answer is 50 oranges. (assuming they all weigh the same)
Answer:
0.1225
Step-by-step explanation:
Given
Number of Machines = 20
Defective Machines = 7
Required
Probability that two selected (with replacement) are defective.
The first step is to define an event that a machine will be defective.
Let M represent the selected machine sis defective.
P(M) = 7/20
Provided that the two selected machines are replaced;
The probability is calculated as thus
P(Both) = P(First Defect) * P(Second Defect)
From tge question, we understand that each selection is replaced before another selection is made.
This means that the probability of first selection and the probability of second selection are independent.
And as such;
P(First Defect) = P (Second Defect) = P(M) = 7/20
So;
P(Both) = P(First Defect) * P(Second Defect)
PBoth) = 7/20 * 7/20
P(Both) = 49/400
P(Both) = 0.1225
Hence, the probability that both choices will be defective machines is 0.1225
