Question

Tim's bean sprout grew 3/ inches. Teegan's bean sprout grew 2 3/4 inches. How many more inches did Tim's bean sprout grow than Teegan's? First, estimate the difference mentally and explain your reasoning. Then find the actual difference.

Answer 1

Answer:

Tim's bean sprout grow by more than $\frac{5}{8} \text{ inches}$.

Step-by-step explanation:

We are given that Tim's bean sprout grew 3 3/8 inches. Teegan's bean sprout grew 2 3/4 inches.

We have to find how many more inches did Tim's bean sprout grow than Teegan's.

Firstly, converting both the mixed fractions in improper fraction get;

Tim's bean sprout grew = $3\frac{3}{8}$ = $\frac{27}{8} \text{ inches}$

Teegan's bean sprout grew = $2\frac{3}{4}$ = $\frac{11}{4} \text{ inches}$

Since the denominator of both the fractions is not the same, so we can't compare them both as which is larger or smaller.

Tim's bean sprout grew = $\frac{27\times 1}{8\times 1} = \frac{27}{8} \text{ inches}$

Teegan's bean sprout grew = $\frac{11 \times 2}{4\times 2}=\frac{22}{8} \text{ inches}$

Now, we can clearly see that Tim's bean sprout grew more than Teegan's bean sprout.

So, Tim's bean sprout grow by more than = $\frac{27}{8}- \frac{22}{8}$ = $\frac{5}{8} \text{ inches}$

Hence, Tim's bean sprout grow by more than $\frac{5}{8} \text{ inches}$.