Answer:
![\huge\boxed{\sqrt[3]{c^4}=c^\frac{4}{3}}](https://tex.z-dn.net/?f=%5Chuge%5Cboxed%7B%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D%7D)
Step-by-step explanation:
![\sqrt[n]{a^m}=a^\frac{m}{n}\\\\\text{therefore}\\\\\sqrt[3]{c^4}=c^\frac{4}{3}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5Em%7D%3Da%5E%5Cfrac%7Bm%7D%7Bn%7D%5C%5C%5C%5C%5Ctext%7Btherefore%7D%5C%5C%5C%5C%5Csqrt%5B3%5D%7Bc%5E4%7D%3Dc%5E%5Cfrac%7B4%7D%7B3%7D)
Answer:
56
Step-by-step explanation:
Subtract 32 to both sides to the equation becomes -5x^2 + 7x + 9 = 0.
To solve this equation, we can use the quadratic formula. The quadratic formula solves equations of the form ax^2 + bx + c = 0
x = [ -b ± √(b^2 - 4ac) ] / (2a)
x = [ -7 ± √(7^2 - 4(-5)(9)) ] / ( 2(-5) )
x = [ -7 ± √(49 - (-180) ) ] / ( -10 )
x = [ -7 ± √(229) ] / ( -10)
x = [ -7 ± sqrt(229) ] / ( -10 )
x = 7/10 ± -sqrt(229)/10
The answers are 7/10 + sqrt(229)/10 and 7/10 - sqrt(229)/10.
Its I=prt
so plug it in
I=300(.06)3 i got .06 because you have 6% you have to move the decimal the left twice 0.06 is what you get
now its basic multiplying
300 times .06 times 3
so it would be 54
I=$54
the balence you get from adding the P to the I so the balence would be 356
Bal=$356
The vertical distance is 5 + 8 = 13
the horizantal distance is 3 +3 = 6
then just do pythag therom
6^2 + 13^2 = c^2
205 = c^2
<span>√205 = c
</span>
