The answer is 18^8 because u add exponents
I suspect you meant
"How many numbers between 1 and 100 (inclusive) are divisible by 10 or 7?"
• Count the multiples of 10:
⌊100/10⌋ = ⌊10⌋ = 10
• Count the multiples of 7:
⌊100/7⌋ ≈ ⌊14.2857⌋ = 14
• Count the multiples of the LCM of 7 and 10. These numbers are coprime, so LCM(7, 10) = 7•10 = 70, and
⌊100/70⌋ ≈ ⌊1.42857⌋ = 1
(where ⌊<em>x</em>⌋ denotes the "floor" of <em>x</em>, meaning the largest integer that is smaller than <em>x</em>)
Then using the inclusion/exclusion principle, there are
10 + 14 - 1 = 23
numbers in the range 1-100 that are divisible by 10 or 7. In other words, add up the multiples of both 10 and 7, then subtract the common multiples, which are multiples of the LCM.
Part 1:
Given that the length of the chord is 18 cm and the chord is midway the radius of the circle.
Thus, half the angle formed by the chord at the centre of the circle is given by:
Now,
Therefore, the radius of the circle is
10.4 cm to 1 d.p.
Part 2I:
Given that the radius of the circle is 10 cm and the length of chord AB is 8 cm. Thus, half the length of the chord is 4cm. Let the distance of the mid-point O to /AB/ be x and half the angle formed by the chord at the centre of the circle be θ, then
Now,
Part 2II:
Given that the radius of the circle is 10cm and the angle distended is 80 degrees. Let half the length of chord CD be y, then:
Thus, the length of chord CD = 2(6.428) = 12.856 which is approximately
12.9 cm.
Answer:
144i + 81
Step-by-step explanation:
(-3*9i)(-5 + 3i) + 9i
-27i (-5 + 3i) + 9i
FOIL
135i + 81 + 9i
144i + 81
Answer:
C. y = x² - 6x + 10
Step-by-step explanation:
Formula f(x)=a(x-h)^2+k (h,k) is vertex
Y=a (x-3)^2+1
Plug in y intercept
10=a (0-3)2+1
10=-3^2a+1
10=9a+1
9=9a
A=1
Y=(x-3)2 +1
Y=x2-6x+9+1
Y=x2-6x+10
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